如何迭代数据框中的值并将值传递给 Python 中的发送电子邮件函数

How to iterate values from a dataframe and pass the values to a send email function in Python

我有一个数据框 (df) 如下所示

Subject                       To_Address       CC_Address                       Backup_Address
Invoice 2345 is invalid       xyz@gmail.com     koke@gmail,ali@gmail.com         a@gmail.com
Invoice 3456 is invalid       abc@gmail.com     jack@gmail.com,ali.gmail.com     b@gmail.com
Invoice 3673 is invalid       bcd@gmail.com     peach@gmail.com,ali.gmail.com    e@gmail.com
Invoice 8978 is invalid                         rock@gmail.com,ali.gmail.com     c@gmail.com
Invoice 8078 is invalid                         rock@gmail.com,ali.gmail.com     d@gmail.com
Invoice 3173 is invalid       mnb@gmail.com     mone@gmail.com,ali.gmail.com     f@gmail.com

我需要使用

为数据框的每一行发送唯一的电子邮件
Email Subject = df[Subject] ,Email To Address =df[To_Address], Email_CC_Address = df[CC_Address]

还需要添加期望条件,Email To Address 为 null 或 NaN,则应传递 Email To Address =df[Backup_Address]

如何在 python 中完成此操作。

我当前使用静态值运行的代码

def create_message(send_from, send_to,cc_to,subject, plain_text_body):
    message = MIMEMultipart('alternative')
    message['From'] = send_from
    message['To'] = COMMASPACE.join(send_to)
    message['Cc'] = cc_to
    message['Subject'] = subject
    message.attach(MIMEText(plain_text_body, 'plain'))
    return message


subject = "Invoice is invalid"
sender_address = "sender@gmail.com.com"
to = "to@gmail.com"
cc_to = "cc@gmail.com"
mail_content="This is a test message"

message = create_message(sender_address,[to],cc_to,subject,mail_content)

send_message(message)

要遍历 Pandas DataFrame,您可以使用 DataFrame.iterrows().

但是不推荐对 df 进行迭代,因为它被认为是“反模式”..

推荐阅读here

尝试使用 zip:

在数据框中并行遍历行和多列
def create_message(send_from, send_to, cc_to,subject, plain_text_body):
    sender_address = "sender@gmail.com.com"
    mail_content="This is a test message"
    for a, b, c, d in zip(df['Subject'], df['To_Address'], df['CC_Address'], df['Backup_Address']):
        if b == '':
            send_to = d
        else:
            send_to = b
        subject = a
        cc_to = c
        message = MIMEMultipart('alternative')
        message['From'] = send_from
        message['To'] = COMMASPACE.join(send_to)
        message['Cc'] = cc_to
        message['Subject'] = subject
        message.attach(MIMEText(plain_text_body, 'plain'))
        return message


message = create_message(sender_address,[to],cc_to,subject,mail_content)

send_message(message)