如何在 Dart (Flutter) 中获取每个可迭代值的索引号

Question

我需要 index 数字 forEach 可迭代值，因为我想更新我的数据 table。但是为了更新数据 table 我需要列 ID。这就是为什么我想要每个值的索引号并将其分配给> i。有类似的问题解释了如何获取可迭代的索引。但就我而言，我未能映射 CallLogEntry，这就是为什么我无法获取此可迭代值的索引。

Future callLogDB() async {
    Iterable<CallLogEntry> cLog = await CallLog.get();
    final dbHelper = DatabaseHelper.instance;
    int i = 0;
    cLog.forEach((log) async {
      i++;
      // row to insert
      Map<String, dynamic> row = {
        //DatabaseHelper.columnId: 2,
        DatabaseHelper.columnName: '${log.name}',
        DatabaseHelper.columnNumber: '${log.number}',
        DatabaseHelper.columnType: '${log.callType}',
        DatabaseHelper.columnDate:
            '${DateTime.fromMillisecondsSinceEpoch(log.timestamp)}',
        DatabaseHelper.columnDuration: '${log.duration}'
      };
      await dbHelper.insert(row);
      print('CallLog $i:: $row');
    });
    return cLog;
  }

Answer 1

I can not map CallLogEntry.

首先，您需要使用toList()方法将Iterable<CallLogEntry>转换为列表，然后您可以使用asMap()

示例代码

 Iterable<CallLogEntry> cLog = await CallLog.get();
 cLog.toList().asMap().forEach((cLogIndex, callLogEntry) {

      row.forEach((index, data) {

      });

    });

编辑

Future callLogDB() async {
  Iterable<CallLogEntry> cLog = await CallLog.get();
  final dbHelper = DatabaseHelper.instance;
  int i = 0;
  cLog.toList().asMap().forEach((cLogIndex, callLogEntry) {

    Map<String, dynamic> row = {
      //DatabaseHelper.columnId: cLogIndex,
      DatabaseHelper.columnName: '${cLogIndex.name}',
      DatabaseHelper.columnNumber: '${cLogIndex.number}',
      DatabaseHelper.columnType: '${cLogIndex.callType}',
      DatabaseHelper.columnDate:
      '${DateTime.fromMillisecondsSinceEpoch(cLogIndex.timestamp)}',
      DatabaseHelper.columnDuration: '${cLogIndex.duration}'
    };
    await dbHelper.insert(row);

  });
  return cLog;
}

如何在 Dart (Flutter) 中获取每个可迭代值的索引号

How to get index number forEach iterable value in Dart (Flutter)

database

foreach

iterable

dart

flutter