您如何检查字符串是否可转换为 int,如果是,则转换它? (Python,涉及discord.py重写)
How do you check if a string is convertible to an int, and if so, convert it? (Python, involves discord.py rewrite)
我目前正在 Python 制作一个不和谐的机器人。我想创建一个命令,其中您有两个参数选项:
- 一个整数,删除一定数量的消息
- 和单词'all'(字符串)删除频道中的所有消息。
我试过这样的函数来确定它是否是一个字符串...
def isint(s):
try:
int(s)
isint = True
except ValueError:
isint = False
return isint
...但是 returns 这个错误:
TypeError: '<=' not supported between instances of 'str' and 'int'
这是我尝试过的命令的当前最新代码:
@commands.command()
@commands.has_role("Clear Chat Key")
async def clear(self, ctx, amount: typing.Union[str, int] = 10):
number = isint(amount)
if number == False:
if amount == 'all':
await ctx.channel.purge(limit = inf)
else:
await ctx.send('Invalid amount.')
if number == True:
await ctx.channel.purge(limit = amount)
else:
await ctx.send('Invalid amount.')
如果相关,则错误的完整回溯如下:
Traceback (most recent call last):
File "C:\Users794\AppData\Local\Programs\Python\Python38\lib\site-packages\discord\ext\commands\bot.py", line 892, in invoke
await ctx.command.invoke(ctx)
File "C:\Users794\AppData\Local\Programs\Python\Python38\lib\site-packages\discord\ext\commands\core.py", line 797, in invoke
await injected(*ctx.args, **ctx.kwargs)
File "C:\Users794\AppData\Local\Programs\Python\Python38\lib\site-packages\discord\ext\commands\core.py", line 92, in wrapped
raise CommandInvokeError(exc) from exc
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: TypeError: '<=' not supported between instances of 'str' and 'int'
请耐心等待,我是 Python 的新手。
编辑:
感谢您帮助我解决这个问题!这是我在其他人需要时使用的代码:
def is_int(x):
if x.isdigit():
return True
return False
@commands.command()
@commands.has_role("Clear Chat Key")
async def clear(self, ctx, amount: typing.Union[str, int] = 10):
number = is_int(amount)
if number == False:
if amount == 'all':
await ctx.channel.purge(limit = inf)
else:
await ctx.send('Invalid amount.')
if number == True:
amount = int(amount)
await ctx.channel.purge(limit = amount)
else:
await ctx.send('Invalid amount.')
再次感谢您的帮助!
试试用这个代替你的函数 isint
:
# clear function
number = amount.__class__.__name__ == 'int'
您可以使用字符串的 .isdigit()
方法。
请记住,这将 return False
用于否定:
>>> my_str = "123"
>>> my_str.isdigit()
True
>>> other_str = "-123"
>>> my_str.isdigit()
False
工作示例:
def is_int(some_value):
if some_input.isdigit():
return True
return False
some_input = input("Enter some numbers or words!\n-> ")
print(is_int(some_input))
参考:
我目前正在 Python 制作一个不和谐的机器人。我想创建一个命令,其中您有两个参数选项:
- 一个整数,删除一定数量的消息
- 和单词'all'(字符串)删除频道中的所有消息。
我试过这样的函数来确定它是否是一个字符串...
def isint(s):
try:
int(s)
isint = True
except ValueError:
isint = False
return isint
...但是 returns 这个错误:
TypeError: '<=' not supported between instances of 'str' and 'int'
这是我尝试过的命令的当前最新代码:
@commands.command()
@commands.has_role("Clear Chat Key")
async def clear(self, ctx, amount: typing.Union[str, int] = 10):
number = isint(amount)
if number == False:
if amount == 'all':
await ctx.channel.purge(limit = inf)
else:
await ctx.send('Invalid amount.')
if number == True:
await ctx.channel.purge(limit = amount)
else:
await ctx.send('Invalid amount.')
如果相关,则错误的完整回溯如下:
Traceback (most recent call last):
File "C:\Users794\AppData\Local\Programs\Python\Python38\lib\site-packages\discord\ext\commands\bot.py", line 892, in invoke
await ctx.command.invoke(ctx)
File "C:\Users794\AppData\Local\Programs\Python\Python38\lib\site-packages\discord\ext\commands\core.py", line 797, in invoke
await injected(*ctx.args, **ctx.kwargs)
File "C:\Users794\AppData\Local\Programs\Python\Python38\lib\site-packages\discord\ext\commands\core.py", line 92, in wrapped
raise CommandInvokeError(exc) from exc
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: TypeError: '<=' not supported between instances of 'str' and 'int'
请耐心等待,我是 Python 的新手。
编辑: 感谢您帮助我解决这个问题!这是我在其他人需要时使用的代码:
def is_int(x):
if x.isdigit():
return True
return False
@commands.command()
@commands.has_role("Clear Chat Key")
async def clear(self, ctx, amount: typing.Union[str, int] = 10):
number = is_int(amount)
if number == False:
if amount == 'all':
await ctx.channel.purge(limit = inf)
else:
await ctx.send('Invalid amount.')
if number == True:
amount = int(amount)
await ctx.channel.purge(limit = amount)
else:
await ctx.send('Invalid amount.')
再次感谢您的帮助!
试试用这个代替你的函数 isint
:
# clear function
number = amount.__class__.__name__ == 'int'
您可以使用字符串的 .isdigit()
方法。
请记住,这将 return False
用于否定:
>>> my_str = "123"
>>> my_str.isdigit()
True
>>> other_str = "-123"
>>> my_str.isdigit()
False
工作示例:
def is_int(some_value):
if some_input.isdigit():
return True
return False
some_input = input("Enter some numbers or words!\n-> ")
print(is_int(some_input))
参考: