获取绑定内置函数的本地方法实例

Question

Python 数据模型的 partially documented 行为是 __getattribute__ 不绑定“内置”函数：

import logging, numpy
class TestBind:
    nobind = print
    nobind2 = numpy.array
    binds = logging.error
    def binds2(self): pass

print(TestBind.nobind)
print(TestBind.nobind2)
print(TestBind.binds)
print(TestBind.binds2)
# <built-in function print>
# <built-in function array>
# <function error at 0x1feedbeed>
# <function TestBind.binds2 at 0x1feedbeef>

t = TestBind()

print(t.nobind)
print(t.nobind2)
print(t.binds)
print(t.binds2)
# <built-in function print>
# <built-in function array>
# <bound method error of <__main__.TestBind object at 0x1beefcafe>>
# <bound method TestBind.binds2 of <__main__.TestBind object at 0x1beefcafe>>

print(type(t.binds))
# method

没有等同于classmethod/staticmethod 的内置“instancemethod”描述符。可以定义一个，例如

from functools import partial
class instancemethod: 
    __slots__ = '_func',
    def __init__(self, func): 
        self._func = func 
    def __get__(self, inst, cls): 
        return self._func if inst is None else partial(self._func, inst)

class TestBind:
    ibinds = instancemethod(logging.error)
    ...

但结果自然不是 method 对象，并且缺少绑定方法的属性：

print(t.ibinds)
# functools.partial(<function error at 0x1feedbeed>, <__main__.TestBind object at 0x1051af310>)
t.ibinds.__self__  # AttributeError
t.ibinds.__name__  # AttributeError
t.ibinds.__func__  # AttributeError
t.ibinds.__doc__  # wrong doc

是否可以编写一些 instancemethod 描述符（或其他任何东西）来为 C 定义的函数生成绑定 method 实例？

分辨率：

根据莫妮卡下面我使用的回答

from types import MethodType

class instancemethod:
    """
    Convert a function to be an instance method.
    """
    __slots__ = '_func',
    def __init__(self, func):
        self._func = func
    def __get__(self, inst, owner=None):
        return self._func if inst is None else MethodType(self._func, inst)

Answer 1

可以直接构造方法对象types.MethodType:

import types

class instancemethod:
    def __init__(self, func):
        self.func = func
    def __get__(self, instance, owner=None):
        if instance is None:
            return self.func
        return types.MethodType(self.func, instance)

请注意，types.MethodType 的签名可能会更改。它在 Python 2 中曾经不同，当时未绑定的方法对象仍然存在。

获取绑定内置函数的本地方法实例

Obtain a native method instance that binds a built-in function

python

cpython

分辨率：