用所有数字替换每个元音以找到加密代码

Question

所以我必须替换名称列表中的每个元音以匹配加密代码，所以我需要的是，例如，对于“Andre”，我需要得到：0ndr0、0ndr1、0ndr2、0ndr3 ... 1ndr1、1ndr2 ... 9ndr5 ... 9ndr9

这是我所做的简化版本：

def testVoyellePrenom():
    voyelle = ["A", "E", "I", "O", "U", "Y"]
    myNumbers = [a + 1 for a in range(-1,9)]
    myNumbers.reverse()
    pre = "ANDRE"
    testing = ""
    for x in pre:
        if(x in voyelle):
            for nb in myNumbers:
                pre = pre.replace(x,str(nb))
                x = str(nb)
                testing = pre
                print(testing)

Output :
9NDRE
8NDRE
7NDRE
6NDRE
5NDRE
4NDRE
3NDRE
2NDRE
1NDRE
0NDRE
0NDR9
0NDR8
0NDR7
0NDR6
0NDR5
0NDR4
0NDR3
0NDR2
0NDR1
0NDR0

Expected output :

...
0NDR0
1NDR9
1NDR8
1NDR7
1NDR6
1NDR5
1NDR4
1NDR3
1NDR2
1NDR1
1NDR0
....

Answer 1

这是一个解决方案。基本逻辑是：

找出元音的所有位置(vowel_inx)。
创建这些位置的所有数字组合的叉积。
循环这个叉积，并通过将数字分配到原始术语中相应的位置来创建新词。

    vowels = ["A", "E", "I", "O", "U", "Y"]
    pre = "ANDRE"
    import itertools
    vowel_inx = [i for i in range(len(pre)) if pre[i] in vowels ]
    
    ranges = [range(10) for _ in vowel_inx]
    for comb in itertools.product(*ranges):
        pw = list(pre)
        for i in range(len(vowel_inx)):
            pw[vowel_inx[i]] = str(comb[i])
        print ("".join(pw))

输出为：

0NDR0
0NDR1
0NDR2
0NDR3
0NDR4
0NDR5
0NDR6
0NDR7
0NDR8
0NDR9
1NDR0
1NDR1
1NDR2
...

Answer 2

正确的做法是：

voyelle = ["A", "E", "I", "O", "U", "Y"]


def permute_single_index(word, index):
    permutations = []
    word_left = word[0:index]
    word_right = word[index+1:]
    for i in reversed(range(10)):
        permutations.append(f"{word_left}{i}{word_right}")
    return permutations


def testVoyellePrenom(pre):
    upper_pre = pre.upper()
    replace_indexes = [i for i, x in enumerate(upper_pre) if x in voyelle]

    permutations = [upper_pre]

    for ri in replace_indexes:
        new_permutations = []
        for word in permutations:
            new_permutations += permute_single_index(word, ri)
        permutations += new_permutations

    print(permutations)
    print(len(permutations))


def main():
    testVoyellePrenom("Andre")


if __name__ == "__main__":
    main()

你最终得到 121 个排列。

用所有数字替换每个元音以找到加密代码

Replace every vowels by all the numbers to find the encrypted code

python

encryption

hashcode