JS - URLSearchParams - 添加参数
JS - URLSearchParams - add parameters
我似乎无法将 parameters/queries 添加到 URL。我正在尝试向 url 添加参数。我正在尝试使用 .set() 和 .append() 来做这件事,但似乎都没有按照我的想法去做。我是否误解了这些方法的用途。所需的输出应为:
代码:
const url = new URL('/v2/top-headlines', 'http://newsapi.org')
const params = new URLSearchParams(url.search);
params.set('country', 'gb');
params.append('q', 'some_word')
console.log(url); // All good http://newsapi.org/v2/top-headlines
console.log(url.search); // empty object
console.log(params); // Empty string
你是故意的
const url = new URL('http://newsapi.org/v2/top-headlines');
url.searchParams.set('country', 'gb');
url.searchParams.set('q', 'some_word');
console.log(url);
// separately setting the searchParams
/*
const url = new URL('/v2/top-headlines', 'http://newsapi.org'); // (relative,base)
const params = new URLSearchParams(url.search); // if the url had a queryString already
params.set('country', 'gb');
params.set('q', 'some_word');
url.search = params;
console.log(url);
*/
试试这个
const url = new URL("/v2/top-headlines", "http://newsapi.org");
url.searchParams.append("country", "gb");
url.searchParams.append("q", "some word");
console.log(url.toString());
见
我似乎无法将 parameters/queries 添加到 URL。我正在尝试向 url 添加参数。我正在尝试使用 .set() 和 .append() 来做这件事,但似乎都没有按照我的想法去做。我是否误解了这些方法的用途。所需的输出应为:
代码:
const url = new URL('/v2/top-headlines', 'http://newsapi.org')
const params = new URLSearchParams(url.search);
params.set('country', 'gb');
params.append('q', 'some_word')
console.log(url); // All good http://newsapi.org/v2/top-headlines
console.log(url.search); // empty object
console.log(params); // Empty string
你是故意的
const url = new URL('http://newsapi.org/v2/top-headlines');
url.searchParams.set('country', 'gb');
url.searchParams.set('q', 'some_word');
console.log(url);
// separately setting the searchParams
/*
const url = new URL('/v2/top-headlines', 'http://newsapi.org'); // (relative,base)
const params = new URLSearchParams(url.search); // if the url had a queryString already
params.set('country', 'gb');
params.set('q', 'some_word');
url.search = params;
console.log(url);
*/
试试这个
const url = new URL("/v2/top-headlines", "http://newsapi.org");
url.searchParams.append("country", "gb");
url.searchParams.append("q", "some word");
console.log(url.toString());
见