制作 java class for soap xml 字符串

Question

如何将这个 xml 字符串变成 java 对象？我尝试了各种方法，也许是 xml?

的格式

我正在使用 java 11，我通过发送 post 请求获得了 SOAP 响应。我希望能够使用 outXML 字符串。对于 Envelope、Body、TransmitResponse、outXML，我确实有其他 classes。但我希望至少能够先调用 root。

错误：

javax.xml.bind.UnmarshalException: unexpected element 
(uri:"http://schemas.xmlsoap.org/soap/envelope/", local:"Envelope"). 
Expected elements are <{http://schemas.xmlsoap.org/soap/envelope/}SOAP-ENV:Envelope>

xml 文件

<?xml version="1.0"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/">
    <SOAP-ENV:Body SOAP-ENC:encodingStyle="http://schemas.xmlsoap.org/soap/envelope/">
        <NS1:TransmitResponse xmlns:NS1="urn:TransmitterIntf-ITransmitter">
            <return xsi:type="xsd:int">0</return>
            <outXML xsi:type="xsd:string">message</outXML>
        </NS1:TransmitResponse>
    </SOAP-ENV:Body>
</SOAP-ENV:Envelope>

信封class:

package com.example

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;

@XmlType(name = "", propOrder = { "body" })
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "SOAP-ENV:Envelope", namespace = "http://schemas.xmlsoap.org/soap/envelope/")
public class Envelope {
    
    @XmlElement(name = "SOAP-ENV:Body")
    String body;

    // Getter Methods

    public String getBody() {
        return body;
    }

    // Setter Methods

    public void setBody(String body) {
        this.body = body;
    }

}

实施：

            JAXBContext jaxbContext = JAXBContext.newInstance( Envelope.class );
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            StringBuffer xmlStr = new StringBuffer( response.getBody() );
            
            Envelope itransmit = (Envelope) jaxbUnmarshaller.unmarshal( new StreamSource( new StringReader(xmlStr.toString())));
            
            System.out.println(itransmit.getBody());
            return response.toString();

Answer 1

生成 class 的最简单方法是使用 wsdl to java 插件。例如，如果您使用 CXF 和 maven，则可以使用 https://cxf.apache.org/docs/maven-cxf-codegen-plugin-wsdl-to-java.html。这将为您生成 java 代码。

你也可以试试，这是未经测试的代码：

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "Envelope", namespace = "http://schemas.xmlsoap.org/soap/envelope/")
public class Envelope {
    
    @XmlElement(name = "Body", namespace="http://schemas.xmlsoap.org/soap/envelope/")
    String body;

    // Getter Methods

    public String getBody() {
        return body;
    }

    // Setter Methods

    public void setBody(String body) {
        this.body = body;
    }

}

制作 java class for soap xml 字符串

Making java class for soap xml string

java

xml

spring

web-services

jaxb