rspec 测试一个 class 方法给出对象未被侦测或存根错误
rspec testing a class method giving object not spied or stubbed error
Rspec 测试
我有 class 呼叫客户。
class Client
class << self
def shutdown
puts 'shutting down the producer gracefully'
@producer ||= k_producer.producer(opts)
@producer.shutdown
end
private
def k_producer
Kafka.new([127.0.0.1:9092], { required_acks: :all })
end
end
end
我想测试关机 class 方法,但我不明白存根或间谍的概念。
我正在尝试这种方式
RSpec.describe Client do
describe "Client.shutdown" do
it "calls shutdown" do
described_class.shutdown
expect(described_class).to have_received(:shutdown)
end
end
end
我收到此错误,我不知道如何告诉 rspec 我的 class 中有 @producer 并调用了它关闭。
Client (class)> expected to have received shutdown, but that object is not a spy or method has not been stubbed
您从未将 described_class
设置为间谍。您可以将其设为 partial double with allow
.
RSpec.describe Client do
describe "Client.shutdown" do
it "calls shutdown" do
allow(described_class).to receive(:shutdown)
described_class.shutdown
expect(described_class).to have_received(:shutdown)
end
end
end
但是,这个测试是同义反复。您只是在测试名为 Client.shutdown
的测试。测试调用 @producer.shutdown
更有用。
@producer 获取有点麻烦。通过为其内部对象添加访问器,我们可以使 Client 更易于测试,总体上更灵活。
class Client
class << self
# Define only the writers: producer= and kafka=
attr_writer :producer, :kafka
# Define the readers ourselves with our defaults.
def producer
@producer ||= kafka.producer(opts)
end
def kafka
@kafka ||= Kafka.new(["127.0.0.1:9092"], { required_acks: :all })
end
def shutdown
puts 'shutting down the producer gracefully'
producer.shutdown
end
end
end
现在我们制作一个间谍,并将其设置为生产者。
RSpec.describe Client do
describe "Client.shutdown" do
it "calls @producer.shutdown" do
producer = spy("producer")
described_class.producer = producer
described_class.shutdown
expect(producer).to have_received(:shutdown)
end
end
end
Rspec 测试
我有 class 呼叫客户。
class Client
class << self
def shutdown
puts 'shutting down the producer gracefully'
@producer ||= k_producer.producer(opts)
@producer.shutdown
end
private
def k_producer
Kafka.new([127.0.0.1:9092], { required_acks: :all })
end
end
end
我想测试关机 class 方法,但我不明白存根或间谍的概念。
我正在尝试这种方式
RSpec.describe Client do
describe "Client.shutdown" do
it "calls shutdown" do
described_class.shutdown
expect(described_class).to have_received(:shutdown)
end
end
end
我收到此错误,我不知道如何告诉 rspec 我的 class 中有 @producer 并调用了它关闭。
Client (class)> expected to have received shutdown, but that object is not a spy or method has not been stubbed
您从未将 described_class
设置为间谍。您可以将其设为 partial double with allow
.
RSpec.describe Client do
describe "Client.shutdown" do
it "calls shutdown" do
allow(described_class).to receive(:shutdown)
described_class.shutdown
expect(described_class).to have_received(:shutdown)
end
end
end
但是,这个测试是同义反复。您只是在测试名为 Client.shutdown
的测试。测试调用 @producer.shutdown
更有用。
@producer 获取有点麻烦。通过为其内部对象添加访问器,我们可以使 Client 更易于测试,总体上更灵活。
class Client
class << self
# Define only the writers: producer= and kafka=
attr_writer :producer, :kafka
# Define the readers ourselves with our defaults.
def producer
@producer ||= kafka.producer(opts)
end
def kafka
@kafka ||= Kafka.new(["127.0.0.1:9092"], { required_acks: :all })
end
def shutdown
puts 'shutting down the producer gracefully'
producer.shutdown
end
end
end
现在我们制作一个间谍,并将其设置为生产者。
RSpec.describe Client do
describe "Client.shutdown" do
it "calls @producer.shutdown" do
producer = spy("producer")
described_class.producer = producer
described_class.shutdown
expect(producer).to have_received(:shutdown)
end
end
end