Python。在 1 行加入特定行

Python. Join specific lines on 1 line

假设我有这个文件:

1
17:02,111
Problem report related to
router

2
17:05,223
Restarting the systems

3
18:02,444
Must erase hard disk
now due to compromised data

我想要这个输出:

1
17:02,111
Problem report related to router

2
17:05,223
Restarting the systems

3
18:02,444
Must erase hard disk now due to compromised data

一直在 bash 尝试并找到了一种接近的解决方案,但我不知道如何在 Python 上执行此操作。

提前致谢

如果你想删除 extea 线:

为了这个目的,如果该行后面没有空新行,或者该行之前应该有一个与以下正则表达式匹配的行 ^\d{2}:\d{2},\d{3}\s$.

因此,为了在每次迭代中访问下一行,您可以使用 itertools.tee 从名称为 temp 的主文件对象创建一个文件对象,并在其上应用 next 函数.并使用 re.match 匹配正则表达式。

from itertools import tee
import re
with open('ex.txt') as f,open('new.txt','w') as out:
    temp,f=tee(f)
    next(temp)
    try:
        for line in f:
            if next(temp) !='\n' or re.match(r'^\d{2}:\d{2},\d{3}\s$',pre):
                out.write(line)
            pre=line
    except :
        pass

结果:

1
17:02,111
Problem report related to

2
17:05,223
Restarting the systems

3
18:02,444
Must erase hard disk

如果您想将其余部分连接到第三行:

如果您想将第三行之后的其余行连接到第三行,您可以使用以下正则表达式来查找后跟 \n\n 或文件末尾 ($) 的所有块:

r"(.*?)(?=\n\n|$)"

然后根据日期格式的行拆分块并将各部分写入输出文件,但请注意,您需要将第 3 部分中的新行替换为 space :

ex.txt:

1
17:02,111
Problem report related to
router
another line


2
17:05,223
Restarting the systems

3
18:02,444
Must erase hard disk
now due to compromised data
line 5
line 6
line 7

演示:

def splitter(s):
    for x in re.finditer(r"(.*?)(?=\n\n|$)", s,re.DOTALL):
          g=x.group(0)
          if g:
            yield g

import re
with open('ex.txt') as f,open('new.txt','w') as out:
    for block in splitter(f.read()):
        first,second,third= re.split(r'(\d{2}:\d{2},\d{3}\n)',block)
        out.write(first+second+third.replace('\n',' '))

结果:

1
17:02,111
Problem report related to router another line
2
17:05,223
Restarting the systems
3
18:02,444
Must erase hard disk now due to compromised data line 5 line 6 line 7

:

在这个答案中,splitter 函数 returns 一个生成器,当您处理大文件并拒绝在内存中存储不可用的行时非常高效。

x="""1
17:02,111
Problem report related to
router

2
17:05,223
Restarting the systems

3
18:02,444
Must erase hard disk
now due to compromised data
or something"""
def repl(matchobj):
    ll=matchobj.group().split("\n")
    return "\n".join(ll[:3])+" "+" ".join(ll[3:])
print re.sub(r"\b\d+\n\d+:\d+,\d+\b[\s\S]*?(?=\n{2}|$)",repl,x)

您可以将 re.sub 与您自己的自定义替换功能一起使用。

当且仅当文件符合您给定的示例时,这才有效

注:

There may be a faster way if regex is used and it might also be simpler 但想以合乎逻辑的方式进行

代码:

inp=open("output.txt","r")
inp=inp.read().split("\n")
print inp
tempString=""
output=[]
w=0

for s in inp:
    if s:
        if any(c.isalpha() for c in s):
            tempString=tempString+" "+s
        else:
            w=0
            if tempString:
                output.append(tempString.strip())
                tempString=""
            output.append(s)       

    else:
        if tempString:
            output.append(tempString.strip())
            tempString=""
        output.append(" ")
if tempString:
    output.append(tempString.strip())


print "\n".join(output)
out=open("newoutput.txt","w")
out.write("\n".join(output))
out.close()

输入:

1
17:02,111
Problem report related to
2 router

2
17:05,223
Restarting the systems

3
18:02,444
Must erase hard disk
now due to compromised data

4
17:02,111
Problem report related to
router

输出:

1
17:02,111
Problem report related to 2 router

2
17:05,223
Restarting the systems

3
18:02,444
Must erase hard disk now due to compromised data

4
17:02,111
Problem report related to router