如何从字典中提取值并将它们格式化成一个句子

Question

这是我必须为这个问题做的，我不确定格式。这是基于 python 3.4 所以不能使用 f' 字符串。

这是问题所在：

创建一个函数，将字典作为参数，returns 包含有关城市的信息的字符串。城市事实需要从字典中提取三个属性：

name
population
continent

字符串应采用以下格式：X 的人口为 Y，位于 Z（其中 X 是城市名称，Y 是人口，Z 是城市所在的大陆）。例子

city_facts({
  name: "Paris",
  population: "2,140,526",
  continent: "Europe"
}) ➞ "Paris has a population of 2,140,526 and is situated in Europe"
city_facts({
  name: "Tokyo",
  population: "13,929,286",
  continent: "Asia"
}) ➞ "Tokyo has a population of 13,929,286 and is situated in Asia"*

这是我最初想出的，但它不起作用，因为Python 3.4 不存储字典值的顺序。

def city_facts(city):
    info = list(city.values())
    return '{} has a population of {} and is situated in {}'.format(info[0], info[2], info[1])

如何根据字典值填空？上面的代码不起作用，因为 python 3.4 不存储字典值的顺序。基于 Python 3.4，我需要做什么来解决这个问题？

Answer 1

你可以直接用这样的键访问字典

city = {"name": "Paris", "population": "2,140,526", "continent": "Europe"}


def city_facts(city):
    return "{} has a population of {} and is situated in {}".format(
        city["name"], city["population"], city["continent"]
    )

print(city_facts(city))

输出：

Paris has a population of 2,140,526 and is situated in Europe

Answer 2

您可以在 str.format 中使用关键字参数：

city = {"name": "Paris", "population": "2,140,526", "continent": "Europe"}
print("{name} has a population of {population} and is situated in {continent}".format(**city))

打印：

Paris has a population of 2,140,526 and is situated in Europe

Answer 3

也许这段代码可以帮到你。我将你的字典解构为一个列表，然后我做了一个映射函数来为每个字典制作一个字符串。这是代码。

city_facts = [{
  "name": "Paris",
  "population": "2,140,526",
  "continent": "Europe"
},
{
  "name": "Tokyo",
  "population": "13,929,286",
  "continent": "Asia"
}]
# im not sure what version of python able to use format string like below
result = list(map(lambda data: f'{data["name"]} has a population of {data["population"]} and is situated in {data["continent"]}', city_facts))
# you can also use this format string for your version python 3.4
result = list(map(lambda data: '{} has a population of {} and is situated in {}'.format(data["name"],data["population"],data["continent"]), city_facts))
# the result will be a list type, if you want to print as a single string, you can make an iteration to the list
print(result)

Answer 4

f-strings

city = {"name": "Paris", "population": "2,140,526", "continent": "Europe"}
def city_facts(city):
    return f"{city["name"]} has a population of {city["population"]} and is situated in {city["continent"]}")
print(city_facts(city))

如何从字典中提取值并将它们格式化成一个句子

How to extract values from dictionary and format them into a sentence

python

dictionary

key-value-store

输出：