如何将参数传递给邮件方法？ Rails 6

Question

我正在使用 Rails 6 和 ActionMailer。每当他的 post 被评论时，我都会向用户发送一封邮件。这是我的代码：

app/mailers/comment_mailer.rb

class CommentMailer < ApplicationMailer
  def comment_mail
    @user = params[:user]

    mail(to: @user.email, subject: "Comments")
  end
end

app/controllers/comments_controller.rb

class CommentsController < ApplicationController
  before_action :authenticate_user!

  def create
    comment = Comment.new(comment_params)
    comment.user_id = current_user.id
    if comment.save
      CommentMailer.with(user: @user).comment_mail.deliver_now
      redirect_to post_path(comment.post.id)
    end
  end

app/views/comment_mailer/comment_mail.haml

%h4
  Hi
  - @user.name
%p Someone commented your post! Click the link below to see it:
  (I haven't done the link step yet)

学习本教程后：https://dev.to/morinoko/sending-emails-in-rails-with-action-mailer-and-gmail-35g4 我遇到了这个错误：

NoMethodError in CommentsController#create
undefined method `email' for nil:NilClass

我的主机：

NoMethodError (undefined method `email' for nil:NilClass):


app/mailers/comment_mailer.rb:5:in `comment_mail'
app/controllers/comments_controller.rb:8:in `create'
Started POST "/comments" for 172.17.0.1 at 2020-07-01 00:32:38 +0000
Cannot render console from 172.17.0.1! Allowed networks: 127.0.0.0/127.255.255.255, ::1
Processing by CommentsController#create as HTML
  Parameters: {"authenticity_token"=>"Mf15U/OG9DX3SKwoBRHE/D/xENBocTtdcS07aUur+p/tGJAWSxYSP65kovzhLXHXBjvs/Wzp2dV4/1+L4nxrdQ==", "comment"=>{"content"=>"well said!", "post_id"=>"2"}, "commit"=>"Comment"}
  User Load (0.5ms)  SELECT "users".* FROM "users" WHERE "users"."id" =  ORDER BY "users"."id" ASC LIMIT   [["id", 1], ["LIMIT", 1]]
   (0.3ms)  BEGIN
  ↳ app/controllers/comments_controller.rb:7:in `create'
  User Load (0.3ms)  SELECT "users".* FROM "users" WHERE "users"."id" =  LIMIT   [["id", 1], ["LIMIT", 1]]
  ↳ app/controllers/comments_controller.rb:7:in `create'
  Post Load (0.4ms)  SELECT "posts".* FROM "posts" WHERE "posts"."id" =  LIMIT   [["id", 2], ["LIMIT", 1]]
  ↳ app/controllers/comments_controller.rb:7:in `create'
  Comment Create (0.7ms)  INSERT INTO "comments" ("content", "user_id", "post_id", "created_at", "updated_at") VALUES (, , , , ) RETURNING "id"  [["content", "well said!"], ["user_id", 1], ["post_id", 2], ["created_at", "2020-07-01 00:32:38.439626"], ["updated_at", "2020-07-01 00:32:38.439626"]]
  ↳ app/controllers/comments_controller.rb:7:in `create'
   (1.1ms)  COMMIT
  ↳ app/controllers/comments_controller.rb:7:in `create'
CommentMailer#comment_email: processed outbound mail in 1.4ms
Completed 500 Internal Server Error in 54ms (ActiveRecord: 3.6ms | Allocations: 29044)

我用 binding.pry 复习了 comment_mail 方法，我有 @user >> nil 作为 return。

Answer 1

假设评论 belong_to posts 或任何正在评论的内容，然后还假设 posts belong_to 是用户。您需要填充该 @user 变量。类似于：

@user = comment.post.user

获取 post 的用户被评论。

我认为这应该可行

CommentMailer.comment_mail(@user).deliver_now

然后更新方法本身

def comment_mail(user)
  @user = user

  mail(to: @user.email, subject: "Comments")
end

如果需要，您也应该能够在邮件视图模板中使用 @user 对象。

Answer 2

当你打电话给CommentMailer.with(user: @user).comment_mail.deliver_now 你还没有真正定义 @user 你提到你有一个用户附加到 post 记录所以使用那个

comment.post.user 所以现在你有

CommentMailer.with(user: comment.post.user).comment_mail.deliver_now

或者你让用户成为comment_mail

的参数

class CommentMailer < ApplicationMailer
  def comment_mail(user)
    @user = user #and this makes @user available in your templates

    mail(to: @user.email, subject: "Comments")
  end
end

正如您所期望的那样称呼它

CommentMailer.comment_mail(comment.post.user).deliver_now #or preferably deliver_later

如何将参数传递给邮件方法？ Rails 6

How to pass params into a mailer method? Rails 6

ruby-on-rails

actionmailer

ruby-on-rails-6