当 Actor returns Future[Option[None]] Akka Http 时抛出异常

Throwing exception when Actor returns Future[Option[None]] Akka Http

我有案例class

case class Fare(flightNumber: String, flightDate: LocalDate, amount: Int)

和演员

class FareDb extends Actor with ActorLogging {

  import FareDb._

  var fares: List[Fare] = List()

  override def receive: Receive = {
    case AddFare(fare) =>
      log.info(s"Adding fare $fare")
      fares = fares :+ fare

    case GetFare(flightNumber, flightDate) =>
      log.info(s"Getting Fare for FlightNumber $flightNumber and FlightDate $flightDate")
      sender() ! fares.find { fare => (flightNumber == fare.flightNumber & flightDate == fare.flightDate) }
  }

}

我也有路线

object FareController extends App with FareJsonProtocol with SprayJsonSupport{
    val fareRoutes =
        (path("api" / "fare") & get & extractLog) { log =>
          parameter(Symbol("flightNumber").as[String],
            Symbol("flightDate").as(stringToLocalDate)) { (flightNumber: String, flightDate: LocalDate) =>
            log.info(s"Searching for Fare with FlightNumber $flightNumber & FlightDate: $flightDate")
            val fareFuture: Future[Option[Fare]] = (fareDb ? GetFare(flightNumber, flightDate)).mapTo[Option[Fare]]
            complete(fareFuture)
          }
        }
}

当我搜索 Fare 并使用 flightNumber 和 flightDate“询问”Actor 时,它 returns 一个 Future[Option[Fare]]。如果是returns一个车费,那就allz好了。我可以只使用 complete(fareFuture) 因为我有 SprayJson。但是如何迎合一个Future[None]呢?。我想为空结果抛出异常并相应地发送 HttpResponse。我们该怎么做?谢谢。

我假设你想 return 404 当你的未来 return 是 None 时。你不需要抛出异常来处理这种情况。

您可以通过以下方式修改路由来处理None.

而不是 complete(fareFuture) 执行以下操作

onSuccess(fareFuture) {
  case Some(fare) => complete(StatusCodes.OK -> fare)
  case None => complete(StatusCodes.NotFound)
}