我正在使用凌空 post 数据到 device.I 通过 wifi.but 在应用程序中连接到它:NoConnectionError!无法连接到 192.168.4.1

I am using volley to post data to a device.I get connected to it by wifi.but in app: NoConnectionError! failed to connect to 192.168.4.1

这是我在我的应用程序 Java 中编写的代码: 我可以通过 python 代码发送数据,但在 android studio 中:failed to connect to 192.168.4.1.

谁能给我一个建议?我真的需要这个来工作。

private void sendDeviceDataPostRequest() {
    RequestQueue queue = Volley.newRequestQueue(this);

    String url = "http://192.168.4.1:3333";

    try {
        String URL = url;
        JSONObject jsonBody = new JSONObject();

        //some data entry


        JsonObjectRequest jsonOblect = new JsonObjectRequest(Request.Method.POST, URL, jsonBody, new Response.Listener<JSONObject>() {
            @Override
            public void onResponse(JSONObject response) {
                try {
                    //code
                } catch (JSONException e) {
                    //code
                }
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                //some code

            }
        }) {
            @Override
            public Map<String, String> getHeaders() throws AuthFailureError {
                //some code
            }
        };
        queue.add(jsonOblect);

    } catch (JSONException e) {
        e.printStackTrace();
    }

使用volley无法解决问题,最后使用TCP socket编程解决了。 这是代码: class myTask 扩展 AsyncTask {

private static Socket s;
private static PrintWriter printWriter;
String send_message = "";
private static String ip = "192.168.4.1";
public static final int port = 3333;
public void set_data(String msg){
    send_message = msg;
}
@Override
protected Void doInBackground(Void... voids) {
    try {
        s = new Socket(ip, port);
        printWriter = new PrintWriter(s.getOutputStream());
        printWriter.write(send_message);
        printWriter.flush();
        printWriter.close();
        s.close();



    }catch (IOException e){
        e.printStackTrace();
    }






    return null;
}

}