如何使用 FactoryBoy 实例化 Django AbstractBaseUser 的子类

How can I instantiate a Subclass of my Django AbstractBaseUser with FactoryBoy

我一直在尝试使用 Factory Boy 来简化单元测试的编写。但是,当我尝试实例化我的自定义用户 class

的实例时,该库不太合作

根据 enter link description here 的指南,自定义 class 继承自 AbstractBaseUserPermissionsMixin

每次我都尝试像这样实例化这个class:

class LogoutTests(TestCase):

    def setUp(self):
        self.employee_password = "foo"
        self.manager_password = "bar"
        self.test_employee_user = EmployeeFactory.create(self.employee_password)
        self.test_manager_user = ManagerFactory.create(self.manager_password)

但是,我不断收到此错误消息:

 factory.errors.FactoryError: Cannot generate instances of abstract factory ManagerFactory; Ensure ManagerFactory.Meta.model is set and ManagerFactory.Meta.abstract is either not set or False.

我已经用其他模型对此进行了测试,只有我的自定义用户模型会生成此错误,因为它可能继承自 AbstractBaseUser。有什么帮助吗?

作为参考,我的自定义用户 class:

class Employee(AbstractBaseUser, PermissionsMixin):

    class Meta:
        abstract = False

    first_name = models.CharField(max_length=250, default="Thibault", blank=False)
    last_name = models.CharField(max_length=250, default="Dupont", blank=False)
    email = models.EmailField(max_length=250, unique=True, blank=False, null=True)
    employee_number = models.OneToOneField(EmployeeNumber)
    is_manager = models.BooleanField(default=False, blank=False)
    is_employed = models.BooleanField(default=True, blank=False)
    is_active = models.BooleanField(default=False)

    objects = EmployeeManager()
    USERNAME_FIELD = 'email'
    REQUIRED_FIELDS = []

    def __str__(self):
        return self.get_full_name()

    def get_short_name(self):
        return '{0}. {1}'.format(self.first_name[0], self.last_name)

    def get_full_name(self):
        return '{0} {1}'.format(self.first_name, self.last_name)

    def email_user(self, subject, message, from_email=None, **kwargs):
        send_mail(subject, message, from_email, [self.email], **kwargs

消息说您还没有告诉 ManagerFactory 应该创建什么模型:ManagerFactory.Meta.model 未设置。

工厂应该是这样的:

import factory
import factory.django

from myapp import models

class ManagerFactory(factory.django.DjangoModelFactory):
    class Meta:
        model = models.Manager

    # Your declarations here