'If not' 避免除零
'If not' to avoid zero division
我下面的代码 returns 当 occupied_spaces
为空时出现 zerodivision
错误。
occupied_spaces = [ ]
cars = occupied_spaces.count(1)
spaces = occupied_spaces.count(0)
if not occupied_spaces:
print('The list is empty')
percentage = cars/len(occupied_spaces) * 100
print(percentage, '%')
有人可以解释为什么会这样吗?
你的问题不清楚,让我猜猜。看起来您想检查占用的空间是否为空,然后打印消息,否则计算百分比。所以代码应该是这样的。如果数组为空函数 len 将 return 你 0
occupied_spaces = [ ]
if not occupied_spaces:
print('The list is empty')
else:
percentage = occupied_spaces.count(1) / len(occupied_spaces) * 100
print(percentage, '%')
看起来像 python 所以您需要正确对齐代码
我下面的代码 returns 当 occupied_spaces
为空时出现 zerodivision
错误。
occupied_spaces = [ ]
cars = occupied_spaces.count(1)
spaces = occupied_spaces.count(0)
if not occupied_spaces:
print('The list is empty')
percentage = cars/len(occupied_spaces) * 100
print(percentage, '%')
有人可以解释为什么会这样吗?
你的问题不清楚,让我猜猜。看起来您想检查占用的空间是否为空,然后打印消息,否则计算百分比。所以代码应该是这样的。如果数组为空函数 len 将 return 你 0
occupied_spaces = [ ]
if not occupied_spaces:
print('The list is empty')
else:
percentage = occupied_spaces.count(1) / len(occupied_spaces) * 100
print(percentage, '%')
看起来像 python 所以您需要正确对齐代码