如何从另一个方法中访问两个方法？

Question

我正在为 The Odin Project 的 Ruby 编程课程创建一个凯撒密码，我的代码已经到了这样的程度，我有一个方法可以接受一个单词和一个移位值 returns 使用相应的散列键和值的加密词。我还有另一种方法，它接受一个句子并将其拆分为一个包含每个单独单词的数组。我想做的是结合这两种方法，这样当你输入一个句子时，单词被分成一个数组，然后使用移位值对数组的每个部分进行加密，然后打印数组中的加密单词回到句子形式。

到目前为止，这是我的代码：

  "a" => 1,
  "b" => 2,
  "c" => 3,
  "d" => 4,
  "e" => 5,
  "f" => 6,
  "g" => 7,
  "h" => 8,
  "i" => 9,
  "j" => 10,
  "k" => 11,
  "l" => 12,
  "m" => 13,
  "n" => 14,
  "o" => 15,
  "p" => 16,
  "q" => 17,
  "r" => 18,
  "s" => 19,
  "t" => 20,
  "u" => 21,
  "v" => 22,
  "w" => 23,
  "x" => 24,
  "y" => 25,
  "z" => 26,
}```

```#multi letter caesar_cipher
def word_cipher(word, shift)
   word.split(//).each {|letter| print @cipher.key(@cipher[letter]+ shift)}
end

> word_cipher("kittens", 2)
=> mkvvgpu

#split sentence string into an array of words
def sentence_array(sentence)
  sentence.split.each { |word| print word.split }
end 

>sentence_array("Look at all of these kittens")
=>["Look"]["at"]["all"]["of"]["these"]["kittens"]

到目前为止我的解决方案是什么

def caesar_cipher(input, shift)
  sentence_array(input) = words
  words.split(//).each {|letter| print @cipher.key(@cipher[letter]+ shift)}
end

caesar_cipher("I love kittens", 2)

这是我第一次在这里发帖，如果我解释得不好，我深表歉意，但我们将不胜感激！

谢谢！

Answer 1

你必须稍微修改一下方法：

#multi letter caesar_cipher
def word_cipher(word, shift)
  output = ''
  word.split(//).each {|letter| output << @cipher.key(@cipher[letter]+ shift)}
  output
end

def sentence_array(sentence)
  sentence.split
end 

#multi letter caesar_cipher
def caesar_cipher(input, shift)
  output = ""
  words = sentence_array(input)
  words.each do |word|
    output << word_cipher(word.downcase, shift)
    output << " " unless word == words.last 
  end
  output.capitalize
end

puts caesar_cipher("I love kittens", 2)

如何从另一个方法中访问两个方法？

How do you access two methods from within another method?

ruby

methods

caesar-cipher