从 2 个输入转换 laravel 中的时间
Convert time in laravel from 2 inputs
我是 Laravel 的初学者。我在我的项目中使用 Laravel 6。
我有 2 个输入:
<input maxlength="5" type="text" name="hours_worked" class="form-control edited valid" value="" required="" onkeypress="return isNumberKey(event)">
<input type="text" name="minutes_worked" class="form-control edited valid" value="" required="" onkeypress="return isNumberKey(event)">
我用这段代码保存到数据库:
WorkingTime::create( $this->request->all()
例如,当有人在字段中键入时,我遇到了问题。 “90”分钟。我在数据库中保存了 90 分钟 - 我想节省 1 小时 30 分钟。
如何使用我的代码实现此目的?
我的架构:
Schema::create('working_times', function (Blueprint $table) {
$table->increments('id');
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('id')->on('clients')->onDelete('cascade');
$table->integer('case_id')->unsigned();
$table->foreign('case_id')->references('id')->on('case_instances')->onDelete('cascade');
$table->integer('user_id')->unsigned();
$table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
$table->smallInteger('hours_worked');
$table->smallInteger('minutes_worked');
$table->string('name');
$table->string('appearance')->nullable();
$table->longText('description')->nullable();
$table->softDeletes();
$table->timestamps();
});
这是一个粗略的解决方案,但不是这样做:
WorkingTime::create($this->request->all());
做:
$data = $this->request->all();
$hours = (int) $data['hours_worked'];
$minutes = (int) $data['minutes_worked'];
$overMinutes = $minutes % 60;
$hours += (int) (($minutes - $overMinutes) / 60);
$minutes = $overMinutes;
$data['hours_worked'] = $hours;
$data['minutes_worked'] = $minutes;
WorkingTime::create($data);
我是 Laravel 的初学者。我在我的项目中使用 Laravel 6。 我有 2 个输入:
<input maxlength="5" type="text" name="hours_worked" class="form-control edited valid" value="" required="" onkeypress="return isNumberKey(event)">
<input type="text" name="minutes_worked" class="form-control edited valid" value="" required="" onkeypress="return isNumberKey(event)">
我用这段代码保存到数据库:
WorkingTime::create( $this->request->all()
例如,当有人在字段中键入时,我遇到了问题。 “90”分钟。我在数据库中保存了 90 分钟 - 我想节省 1 小时 30 分钟。
如何使用我的代码实现此目的?
我的架构:
Schema::create('working_times', function (Blueprint $table) {
$table->increments('id');
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('id')->on('clients')->onDelete('cascade');
$table->integer('case_id')->unsigned();
$table->foreign('case_id')->references('id')->on('case_instances')->onDelete('cascade');
$table->integer('user_id')->unsigned();
$table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
$table->smallInteger('hours_worked');
$table->smallInteger('minutes_worked');
$table->string('name');
$table->string('appearance')->nullable();
$table->longText('description')->nullable();
$table->softDeletes();
$table->timestamps();
});
这是一个粗略的解决方案,但不是这样做:
WorkingTime::create($this->request->all());
做:
$data = $this->request->all();
$hours = (int) $data['hours_worked'];
$minutes = (int) $data['minutes_worked'];
$overMinutes = $minutes % 60;
$hours += (int) (($minutes - $overMinutes) / 60);
$minutes = $overMinutes;
$data['hours_worked'] = $hours;
$data['minutes_worked'] = $minutes;
WorkingTime::create($data);