我如何使用 pytest-django 在每个会话中只创建一次用户对象?

How can I use pytest-django to create a user object only once per session?

首先,我厌倦了这个:

@pytest.mark.django_db
@pytest.fixture(scope='session')
def created_user(django_db_blocker):
    with django_db_blocker.unblock():
        return CustomUser.objects.create_user("User", "UserPassword")

def test_api_create(created_user):
    user = created_user()
    assert user is not None

但是我遇到了 UndefinedTable 错误。因此,以某种方式用 @pytest.mark.django_db 标记我的夹具实际上并没有注册我的 Django 数据库。所以接下来我尝试将 db 对象直接传递给 fixture:

@pytest.fixture(scope='session')
def created_user(db, django_db_blocker):
    with django_db_blocker.unblock():
        return CustomUser.objects.create_user("User", "UserPassword")

def test_api_create(created_user):
    user = created_user()
    assert user is not None

但是我得到一个错误

ScopeMismatch: You tried to access the 'function' scoped fixture 'db' with a 'session' scoped request object, involved factories

最后,为了确认一切正常,我尝试了:

@pytest.fixture
def created_user(db, django_db_blocker):
    with django_db_blocker.unblock():
        return CustomUser.objects.create_user("User", "UserPassword")

def test_api_create(created_user):
    user = created_user()
    assert user is not None

这很好用,但现在我的 create_user 函数每次设置或拆除时都会被调用。这里的解决方案是什么?

@hoefling 有答案,我需要通过 django_db_setup 代替。

@pytest.fixture(scope='session')
def created_user(django_db_setup, django_db_blocker):
    with django_db_blocker.unblock():
        return CustomUser.objects.create_user("User", "UserPassword")