检查 userid 是否与数组中的一个匹配
Check if userid matches one in the array
我正在尝试检查用户 ID 是否在此数组中,如果是,还从中获取“文本”。
数组:
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
我试过 if (staff.user.includes(msg.member.id))
(我认为行不通,但也没有。)
const findUser = (users, id) => users.find(user => user.id === id)
const usersExample = [
{
id: '123456765',
text: 'sdfsdfsdsd'
},
{
id: '654345676',
text: 'fdgdgdg'
}
]
//////////////////
const user = findUser(usersExample, '123456765')
console.log(user && user.text)
数组上的 some 方法用于判断某项是否满足条件,它类似于 find 方法,但 find 方法 returns 是 some 方法 return 所在的项对或错。
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
const isStaff = (staff, id) => staff.some(s => s.user === id);
console.log(isStaff(staff, '123'));
console.log(isStaff(staff, '245569534218469376'));
您可以尝试这样的操作:
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
let item = staff.find(item => item.user == '294597887919128576'); // msg.member.id
if (item) {
console.log(item.text);
}
另一种方法是:
const inArray = (array, id) => array.filter(item => item.user === id).length >= 1;
const users = [
{
user: '245569534218469356',
text: 'foo'
}, {
user: '245564734218469376',
text: 'bar'
}, {
user: '246869534218469376',
text: 'baz'
}
];
console.log(inArray(users, '246869534218469376')); // true
console.log(inArray(users, '222479534218469376')); // false
我正在尝试检查用户 ID 是否在此数组中,如果是,还从中获取“文本”。
数组:
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
我试过 if (staff.user.includes(msg.member.id))
(我认为行不通,但也没有。)
const findUser = (users, id) => users.find(user => user.id === id)
const usersExample = [
{
id: '123456765',
text: 'sdfsdfsdsd'
},
{
id: '654345676',
text: 'fdgdgdg'
}
]
//////////////////
const user = findUser(usersExample, '123456765')
console.log(user && user.text)
数组上的 some 方法用于判断某项是否满足条件,它类似于 find 方法,但 find 方法 returns 是 some 方法 return 所在的项对或错。
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
const isStaff = (staff, id) => staff.some(s => s.user === id);
console.log(isStaff(staff, '123'));
console.log(isStaff(staff, '245569534218469376'));
您可以尝试这样的操作:
const staff = [
{
user: '245569534218469376',
text: 'dev'
},
{
user: '294597887919128576',
text: 'loner'
}
];
let item = staff.find(item => item.user == '294597887919128576'); // msg.member.id
if (item) {
console.log(item.text);
}
另一种方法是:
const inArray = (array, id) => array.filter(item => item.user === id).length >= 1;
const users = [
{
user: '245569534218469356',
text: 'foo'
}, {
user: '245564734218469376',
text: 'bar'
}, {
user: '246869534218469376',
text: 'baz'
}
];
console.log(inArray(users, '246869534218469376')); // true
console.log(inArray(users, '222479534218469376')); // false