合并 2 JSON 个数组（压缩效果）

Question

我不是阵法高手！我正在尝试合并 2 个相互关联的 JSON 数组。本质上，值 A 和 E 存在于 1 个数组中，而它们的索引（0、1、2 等）存在于另一个数组中。这些是我的 2 JSONS...

的示例

JSON1:

"d": [{"A": 0,"B": "foo1","C": "bar1","D": "real1","E": 0},
      {"A": 1,"B": "foo2","C": "bar2","D": "real2""E": 1},
      {"A": 2,"B": "foo3","C": "bar3","D": "real3","E": 2} ]

JSON 2:

    "A": ["this1","this2","this3"]
    "E": ["last1","last2","last3"]

如何使用 PHP 加入，使完成的版本看起来像：

"d": [{"A": "this1","B": "foo1","C": "bar1","D": "real1","E": "last1"},
      {"A": "this2","B": "foo2","C": "bar2","D": "real2","E": "last2"},
      {"A": "this3","B": "foo3","C": "bar3","D": "real3","E": "last3"}]

Answer 1

将JSON解码为数组后，可以循环遍历第一个数组，检查第二个数组中是否存在数组键，如果存在，则将值替换为对应的值第二个数组中的数组：

$array1 = json_decode($json1, true);
$array2 = json_decode($json2, true);

foreach ($array1['d'] as &$arr) {
    foreach ($arr as $key => &$value) {
        if (array_key_exists($key, $array2)) {
            $value = $array2[$key][$value];
        }
    }
}
echo json_encode($array1);

输出：

{
    "d": [
        {
            "A": "this1",
            "B": "foo1",
            "C": "bar1",
            "D": "real1",
            "E": "last1"
        },
        {
            "A": "this2",
            "B": "foo2",
            "C": "bar2",
            "D": "real2",
            "E": "last2"
        },
        {
            "A": "this3",
            "B": "foo3",
            "C": "bar3",
            "D": "real3",
            "E": "last3"
        }
    ]
}

Demo on 3v4l.org

合并 2 JSON 个数组（压缩效果）

Merge 2 JSON arrays (Zip effect)

php

arrays

array-merge