当包含 ice 服务器时,WebRTC 卡在连接状态(远程候选甚至通过 LAN 引起问题)
WebRTC stuck in connecting state when ice servers are included (remote candidates causing issues even over LAN)
我在尝试解决 .
时临时创建了一个没有任何 iceServers
的 RTCPeerConnection
let peer = new RTCPeerConnection();
这在我的本地网络上一直运行良好。
但是,不在同一网络上的设备(例如,4G 手机)无法连接。我记得我必须向 RTCPeerConnection
构造函数添加一些 iceServers
。
let peer = RTCPeerConnection(
{
iceServers: [
{
urls: [
"stun:stun1.l.google.com:19302",
"stun:stun2.l.google.com:19302",
],
},
{
urls: [
"stun:global.stun.twilio.com:3478?transport=udp",
],
},
],
iceCandidatePoolSize: 10,
}
);
这样做之后,我的WebRTC连接就一直卡在连接状态。即使在我的本地网络上,也没有一个连接成功。 (不再是这种情况,请参阅下面的 edit 2)
这是连接状态:
- 冰候补集齐
- 已创建 offer/answer。
- offer/answer和ice candidates通过我的信令服务发送成功。
- 我成功设置了远程和本地描述,并在两端添加了 ice candidates。
- 连接保持连接状态。
- 大约 30 秒后,连接超时并失败。
编辑:看起来比当我将 iceServers
留空时,连接仍然收集冰候选者,所以我假设我的浏览器(chrome) 提供了一个默认的 ice 服务器。在那种情况下,只有我的自定义 ice 服务器(如上所示)导致了问题,而不是浏览器默认设置。
编辑 2:新观察
我已经添加了大量的日志记录,而且每当我确实包含 iceServers
时,我都会注意到一些事情:
每当对等点 A 在一段时间内第一次发起与对等点 B 的连接时,对等点 B 会收集两个 ice 候选者:1 个本地主机候选者和 1 个远程候选者。如上所述,连接失败。
但是当我快速尝试再次连接时...对等点 B 只收集了一个 ice 候选者:本地主机候选者。不聚集远程候选人。我的第一个假设是我正在使用的 STUN 服务器(在本例中可能是 google's)对其服务有某种形式的速率限制。这个场景真正有趣的是,连接成功了!!
远程候选人搞乱连接有些神秘...我希望这些新细节能有所帮助。我被困在这几个月了!而且这两个设备都在我的局域网上,所以我希望远程候选人完全没有影响。
Peer A代码(发起者):
export class WebRTCConnection {
private _RTCPeerConnection: any;
private _fetch: any;
private _crypto: any;
private _entity: any;
private _hostAddress: any;
private _eventHandlers: ConnectionEventHandlers;
private _peer: any;
private _peerChannel: any;
constructor({
entity,
hostAddress,
eventHandlers,
RTCPeerConnection,
fetch,
crypto,
}: {
entity: any,
hostAddress: any,
eventHandlers: ConnectionEventHandlers,
RTCPeerConnection: any,
fetch: any,
crypto: any,
}) {
this._RTCPeerConnection = RTCPeerConnection;
this._fetch = fetch;
this._crypto = crypto;
this._entity = entity;
this._hostAddress = hostAddress;
this._eventHandlers = eventHandlers;
this._initPeer();
}
async _initPeer() {
this._peer = new this._RTCPeerConnection(/* as shown in question */);
let resolveOfferPromise: (value: any) => void;
let resolveIceCandidatesPromise: (value: any[]) => void;
let iceCandidatesPromise: Promise<any[]> = new Promise((resolve, _reject) => {
resolveIceCandidatesPromise = resolve;
});
let offerPromise: Promise<any> = new Promise((resolve, _reject) => {
resolveOfferPromise = resolve;
});
this._peer.onnegotiationneeded = async () => {
let offer = await this._peer.createOffer();
await this._peer.setLocalDescription(offer);
resolveOfferPromise(this._peer.localDescription);
};
this._peer.onicecandidateerror = () => {
// log error
};
let iceCandidates: any[] = [];
this._peer.onicecandidate = async (evt: any) => {
if (evt.candidate) {
// Save ice candidate
iceCandidates.push(evt.candidate);
} else {
resolveIceCandidatesPromise(iceCandidates);
}
};
(async () => {
// No more ice candidates, send on over signaling service
let offer: any = await offerPromise;
let iceCandidates: any[] = await iceCandidatesPromise;
let sigData = // reponse after sending offer and iceCandidates over signaling service
let answer = sigData.answer;
await this._peer.setRemoteDescription(answer);
for (let candidate of sigData.iceCandidates) {
await this._peer.addIceCandidate(candidate);
}
})();
this._peer.onicegatheringstatechange = (evt: any) => {
// log state
};
this._peer.onconnectionstatechange = async () => {
// log state
};
this._peerChannel = this._peer.createDataChannel("...", {
id: ...,
ordered: true,
});
this._peerChannel.onopen = () => {
// log this
};
this._peerChannel.onmessage = (event: any) => {
// do something
};
}
send(msg: any) {
this._peerChannel.send(
new TextEncoder().encode(JSON.stringify(msg)).buffer,
);
}
close() {
if (this._peer) {
this._peer.destroy();
}
}
}
同行B代码:
export class WebRTCConnection {
constructor({ signalData, eventHandlers, RTCPeerConnection }) {
this._eventHandlers = eventHandlers;
this._peer = new RTCPeerConnection(/* as seen above */);
this._isChannelOpen = false;
this._peer.ondatachannel = (event) => {
event.channel.onopen = () => {
this._mainDataChannel = event.channel;
event.channel.onmessage = async (event) => {
// do something
};
this._isChannelOpen = true;
};
};
this._peer.onicecandidateerror = () => {
// log error
};
this._iceCandidates = [];
this._isIceCandidatesFinished = false;
this._iceCandidatesPromise = new Promise((resolve, _reject) => {
this._resolveIceCandidatesPromise = resolve;
});
this._isAnswerFinished = false;
this._isSignalDataSent = false;
this._peer.onicecandidate = async (evt) => {
if (evt.candidate) {
// Save ice candidate
this._iceCandidates.push(evt.candidate);
} else {
// No more ice candidates, send on over signaling service when ready
this._isIceCandidatesFinished = true;
this._resolveIceCandidatesPromise();
this._sendSignalData();
}
};
(async () => {
let sigData = JSON.parse(signalData);
let offer = sigData.offer;
await this._peer.setRemoteDescription(offer);
this._answer = await this._peer.createAnswer();
await this._peer.setLocalDescription(this._answer);
for (let candidate of sigData.iceCandidates) {
await this._peer.addIceCandidate(candidate);
}
this._isAnswerFinished = true;
this._sendSignalData();
})();
this._peer.onconnectionstatechange = async () => {
// log state
};
}
_sendSignalData() {
if (false
|| !this._isIceCandidatesFinished
|| !this._isAnswerFinished
|| this._isSignalDataSent
) {
return;
}
this._isSignalDataSent = true;
this._eventHandlers.onSignal(JSON.stringify({
answer: {
type: this._answer.type,
sdp: this._answer.sdp,
},
iceCandidates: this._iceCandidates,
}));
}
send(msg) {
this._mainDataChannel.send(new TextEncoder().encode(JSON.stringify(msg)));
}
close() {
this._peer.destroy();
}
}
您的代码无需 iceServers
即可在 LAN 上运行,因为 STUN 服务器不用于收集候选主机——您的计算机已经知道其本地 IP 地址——并且候选主机足以在 LAN 上建立 WebRTC 连接。
连接可能失败,因为其中一个对等方位于 symmetric NAT, over which STUN fails to work. You can check whether the network is behind a symmetric NAT by using the code in this page: Am I behind a Symmetric NAT? (This page also provide a JSFiddle 之后,您可以在其中检查控制台消息是否打印“normal nat”或“symmetric nat”。如果它什么都不打印,而 fiddle 正常工作,则意味着您没有获得服务器自反候选者。)
我认为您应该首先在 WAN 上测试您的代码,并与被检查是否支持正常 nat 的同行一起测试。您是否曾经在 WAN 上尝试过通过以太网或 WiFi 连接的两个对等体的代码?好像3G/4G网络经常在对称NAT下。
UPDATE(感谢 @Sean DuBois for the ): A "symmetric NAT", an expression I used above and was introduced in RFC 3489 (March 2003), can be better termed by the updated terminology introduced in RFC 4787 (January 2007). STUN 仅适用于具有“端点独立映射”行为的 NAT。 “对称 NAT”(旧术语)具有“Address-Dependent Mapping”行为或“Address and Port-依赖映射”行为,不是“端点独立映射”行为。
问题是我使用的是 Brave 浏览器。
使用 Chrome 解决了所有问题。
我在尝试解决
iceServers
的 RTCPeerConnection
let peer = new RTCPeerConnection();
这在我的本地网络上一直运行良好。
但是,不在同一网络上的设备(例如,4G 手机)无法连接。我记得我必须向 RTCPeerConnection
构造函数添加一些 iceServers
。
let peer = RTCPeerConnection(
{
iceServers: [
{
urls: [
"stun:stun1.l.google.com:19302",
"stun:stun2.l.google.com:19302",
],
},
{
urls: [
"stun:global.stun.twilio.com:3478?transport=udp",
],
},
],
iceCandidatePoolSize: 10,
}
);
这样做之后,我的WebRTC连接就一直卡在连接状态。即使在我的本地网络上,也没有一个连接成功。 (不再是这种情况,请参阅下面的 edit 2)
这是连接状态:
- 冰候补集齐
- 已创建 offer/answer。
- offer/answer和ice candidates通过我的信令服务发送成功。
- 我成功设置了远程和本地描述,并在两端添加了 ice candidates。
- 连接保持连接状态。
- 大约 30 秒后,连接超时并失败。
编辑:看起来比当我将 iceServers
留空时,连接仍然收集冰候选者,所以我假设我的浏览器(chrome) 提供了一个默认的 ice 服务器。在那种情况下,只有我的自定义 ice 服务器(如上所示)导致了问题,而不是浏览器默认设置。
编辑 2:新观察
我已经添加了大量的日志记录,而且每当我确实包含 iceServers
时,我都会注意到一些事情:
每当对等点 A 在一段时间内第一次发起与对等点 B 的连接时,对等点 B 会收集两个 ice 候选者:1 个本地主机候选者和 1 个远程候选者。如上所述,连接失败。
但是当我快速尝试再次连接时...对等点 B 只收集了一个 ice 候选者:本地主机候选者。不聚集远程候选人。我的第一个假设是我正在使用的 STUN 服务器(在本例中可能是 google's)对其服务有某种形式的速率限制。这个场景真正有趣的是,连接成功了!!
远程候选人搞乱连接有些神秘...我希望这些新细节能有所帮助。我被困在这几个月了!而且这两个设备都在我的局域网上,所以我希望远程候选人完全没有影响。
Peer A代码(发起者):
export class WebRTCConnection {
private _RTCPeerConnection: any;
private _fetch: any;
private _crypto: any;
private _entity: any;
private _hostAddress: any;
private _eventHandlers: ConnectionEventHandlers;
private _peer: any;
private _peerChannel: any;
constructor({
entity,
hostAddress,
eventHandlers,
RTCPeerConnection,
fetch,
crypto,
}: {
entity: any,
hostAddress: any,
eventHandlers: ConnectionEventHandlers,
RTCPeerConnection: any,
fetch: any,
crypto: any,
}) {
this._RTCPeerConnection = RTCPeerConnection;
this._fetch = fetch;
this._crypto = crypto;
this._entity = entity;
this._hostAddress = hostAddress;
this._eventHandlers = eventHandlers;
this._initPeer();
}
async _initPeer() {
this._peer = new this._RTCPeerConnection(/* as shown in question */);
let resolveOfferPromise: (value: any) => void;
let resolveIceCandidatesPromise: (value: any[]) => void;
let iceCandidatesPromise: Promise<any[]> = new Promise((resolve, _reject) => {
resolveIceCandidatesPromise = resolve;
});
let offerPromise: Promise<any> = new Promise((resolve, _reject) => {
resolveOfferPromise = resolve;
});
this._peer.onnegotiationneeded = async () => {
let offer = await this._peer.createOffer();
await this._peer.setLocalDescription(offer);
resolveOfferPromise(this._peer.localDescription);
};
this._peer.onicecandidateerror = () => {
// log error
};
let iceCandidates: any[] = [];
this._peer.onicecandidate = async (evt: any) => {
if (evt.candidate) {
// Save ice candidate
iceCandidates.push(evt.candidate);
} else {
resolveIceCandidatesPromise(iceCandidates);
}
};
(async () => {
// No more ice candidates, send on over signaling service
let offer: any = await offerPromise;
let iceCandidates: any[] = await iceCandidatesPromise;
let sigData = // reponse after sending offer and iceCandidates over signaling service
let answer = sigData.answer;
await this._peer.setRemoteDescription(answer);
for (let candidate of sigData.iceCandidates) {
await this._peer.addIceCandidate(candidate);
}
})();
this._peer.onicegatheringstatechange = (evt: any) => {
// log state
};
this._peer.onconnectionstatechange = async () => {
// log state
};
this._peerChannel = this._peer.createDataChannel("...", {
id: ...,
ordered: true,
});
this._peerChannel.onopen = () => {
// log this
};
this._peerChannel.onmessage = (event: any) => {
// do something
};
}
send(msg: any) {
this._peerChannel.send(
new TextEncoder().encode(JSON.stringify(msg)).buffer,
);
}
close() {
if (this._peer) {
this._peer.destroy();
}
}
}
同行B代码:
export class WebRTCConnection {
constructor({ signalData, eventHandlers, RTCPeerConnection }) {
this._eventHandlers = eventHandlers;
this._peer = new RTCPeerConnection(/* as seen above */);
this._isChannelOpen = false;
this._peer.ondatachannel = (event) => {
event.channel.onopen = () => {
this._mainDataChannel = event.channel;
event.channel.onmessage = async (event) => {
// do something
};
this._isChannelOpen = true;
};
};
this._peer.onicecandidateerror = () => {
// log error
};
this._iceCandidates = [];
this._isIceCandidatesFinished = false;
this._iceCandidatesPromise = new Promise((resolve, _reject) => {
this._resolveIceCandidatesPromise = resolve;
});
this._isAnswerFinished = false;
this._isSignalDataSent = false;
this._peer.onicecandidate = async (evt) => {
if (evt.candidate) {
// Save ice candidate
this._iceCandidates.push(evt.candidate);
} else {
// No more ice candidates, send on over signaling service when ready
this._isIceCandidatesFinished = true;
this._resolveIceCandidatesPromise();
this._sendSignalData();
}
};
(async () => {
let sigData = JSON.parse(signalData);
let offer = sigData.offer;
await this._peer.setRemoteDescription(offer);
this._answer = await this._peer.createAnswer();
await this._peer.setLocalDescription(this._answer);
for (let candidate of sigData.iceCandidates) {
await this._peer.addIceCandidate(candidate);
}
this._isAnswerFinished = true;
this._sendSignalData();
})();
this._peer.onconnectionstatechange = async () => {
// log state
};
}
_sendSignalData() {
if (false
|| !this._isIceCandidatesFinished
|| !this._isAnswerFinished
|| this._isSignalDataSent
) {
return;
}
this._isSignalDataSent = true;
this._eventHandlers.onSignal(JSON.stringify({
answer: {
type: this._answer.type,
sdp: this._answer.sdp,
},
iceCandidates: this._iceCandidates,
}));
}
send(msg) {
this._mainDataChannel.send(new TextEncoder().encode(JSON.stringify(msg)));
}
close() {
this._peer.destroy();
}
}
您的代码无需 iceServers
即可在 LAN 上运行,因为 STUN 服务器不用于收集候选主机——您的计算机已经知道其本地 IP 地址——并且候选主机足以在 LAN 上建立 WebRTC 连接。
连接可能失败,因为其中一个对等方位于 symmetric NAT, over which STUN fails to work. You can check whether the network is behind a symmetric NAT by using the code in this page: Am I behind a Symmetric NAT? (This page also provide a JSFiddle 之后,您可以在其中检查控制台消息是否打印“normal nat”或“symmetric nat”。如果它什么都不打印,而 fiddle 正常工作,则意味着您没有获得服务器自反候选者。)
我认为您应该首先在 WAN 上测试您的代码,并与被检查是否支持正常 nat 的同行一起测试。您是否曾经在 WAN 上尝试过通过以太网或 WiFi 连接的两个对等体的代码?好像3G/4G网络经常在对称NAT下。
UPDATE(感谢 @Sean DuBois for the
问题是我使用的是 Brave 浏览器。
使用 Chrome 解决了所有问题。