oracle12c,sql,分组依据

Question

原来的sql是：

select c.col1,a.col2,count(1) from table_1 a,table_2 b.table_3 c where a.key =b.key and b.no = c.no group by c.col1,a.col2 having count(a.col2) >1;

输出：

c.col1  a.col2 count(1)
aa1     bb1    2
aa1     bb2    3
aa1     bb3    5
aa2     bb8    1
aa2     bb1    4

我试着得到类似于

的输出集

c.col1   count(1)
aa1        10
aa2        5

如何写sql?

Answer 1

我相信只要从 select 中删除 col2 并进行分组，就可以做到这一点。因为 col2 将不再返回，所以您还应该删除 having 语句。我认为它应该看起来像这样：

select
    c.col1,
    count(1)
from
    table_1 a,
    table_2 b,
    table_3 c
where
    a.key = b.key
    and b.no = c.no
group by
    c.col1;

希望对您有所帮助。

Answer 2

使用 sum() 并且仅对 col1

进行分组

select c.col1, sum(a.col2) as total
    from table_1 a,table_2 b.table_3 c 
    where a.key =b.key and b.no = c.no 
    group by c.col1;

输出---

c.col1   total
aa1        10
aa2        5

Answer 3

“简单”选项是使用您当前的查询（重写为使用 JOINs，这是现在 joining 表的首选方式）作为内联视图:

  SELECT col1, SUM (cnt)
    FROM (  SELECT c.col1, a.col2, COUNT (*) cnt     --> your current query begins here
              FROM table_1 a
                   JOIN table_2 b ON a.key = b.key
                   JOIN table_3 c ON c.no = b.no
          GROUP BY c.col1, a.col2
            HAVING COUNT (a.col2) > 1)               --> and ends here
GROUP BY col1;

或者，从 select 中删除 a.col2：

  SELECT c.col1, COUNT (*) cnt
    FROM table_1 a
         JOIN table_2 b ON a.key = b.key
         JOIN table_3 c ON c.no = b.no
GROUP BY c.col1, a.col2
  HAVING COUNT (a.col2) > 1;

oracle12c,sql,分组依据

oracle12c,sql,group by

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oracle

group-by

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