PostgreSQL 函数执行查询

Question

如果满足条件，我想运行查询SQL，但出现以下错误：

错误：一个单独的 $ 链在 «$func$

中或附近未完成

我的SQL查询是：

CREATE OR REPLACE FUNCTION myfunc()
RETURNS TABLE(dateticket date, timeticket time, userid integer, my_all bigint) AS
    $func$
    BEGIN
            IF (SELECT COUNT(DISTINCT(dateticket)) from tickets) = 1 THEN
               RETURN QUERY EXECUTE 'select t.*
               from (select distinct on (userid) dateticket, timeticket, userid,
               count(*) over (partition by userid) as my_all
               from tickets t
               order by userid, dateticket, timeticket) t
               order by my_all, dateticket, timeticket';
            ELSE
               RETURN QUERY EXECUTE 'select t.*
               from (select distinct on (userid) dateticket, timeticket, userid,
               count(*) over (partition by userid) as my_all
               from tickets t
               order by userid, dateticket, timeticket) t
               order by my_all DESC, dateticket DESC, timeticket DESC';
            END IF;
    END;
    $$ LANGUAGE plpgsql;

Answer 1

错误实际上与条件或函数本身的任何内容无关，而是函数创建的语法。函数定义以 $func$ 开始，以 $$ 结束。这行不通。

将 $func$ 更改为 $$ 以修复语法。

Answer 2

你在函数中有两个错误，一个已经回答，另一个是 RETURN table 的列与列名相同在函数内部使用的 select 查询中，这将导致

ERROR: column reference "dateticket" is ambiguous LINE 1: (SELECT COUNT(DISTINCT(dateticket)) from tickets) = 1 ^ DETAIL: It could refer to either a PL/pgSQL variable or a table column. QUERY: (SELECT COUNT(DISTINCT(dateticket)) from tickets) = 1 CONTEXT: PL/pgSQL function myfunc() line 3 at IF ********** Error **********

所以你需要像下面这样修改你的函数

CREATE OR REPLACE FUNCTION myfunc()
RETURNS TABLE(datet_icket date, time_ticket time, user_id integer, myall bigint) AS
    $$
 BEGIN
     IF (SELECT COUNT(DISTINCT(dateticket)) from tickets) = 1 THEN
         RETURN QUERY EXECUTE 'select t.*
         from (select distinct on (userid) dateticket, timeticket, userid,
         count(*) over (partition by userid) as my_all
         from tickets t
         order by userid, dateticket, timeticket) t
         order by my_all, dateticket, timeticket';
     ELSE
          RETURN QUERY EXECUTE 'select t.*
          from (select distinct on (userid) dateticket, timeticket, userid,
          count(*) over (partition by userid) as my_all
          from tickets t
          order by userid, dateticket, timeticket) t
          order by my_all DESC, dateticket DESC, timeticket DESC';
          END IF;
    END;
    $$ LANGUAGE plpgsql;

PostgreSQL 函数执行查询

PostgreSQL function execute query

sql

postgresql

plpgsql

postgresql-9.3