如果为空,如何使用 $subtract 和条件来使用数组中的默认值?
How to use $subtract along with conditions to use a default value from an array, if null?
我正在尝试从聚合管道中的 final
数组和 start
数组中减去值。但也有一些特殊情况需要在减法之前添加一些额外的逻辑。
预期输出:
- I need to subtract nth value of
start
array from nth value of final
array
- And then, get the total sum of subtracted values
特殊情况:
- If nth value of
start
array is NULL, use a start_default value(from the query)
- If nth value of
final
array is NULL, use value from the final_default
array
经过一些聚合阶段后,我的 MongoDB 文档具有以下格式:
Assuming that start_default value = 1
I have commented the way I expect to perform subtractions in each of the group
{
"data": [
{
"key": "TP-1",
"status_map": [
{
"status": "Closed",
"final": [
6,
3
], // Expected Output
"start": [ // sum:6 [(6-2)+(3-1(start_default))=4+2]
2
],
"final_default": [
4
]
},
{
"status": "Done",
"final": [
4
], // Expected Output
"start": [ // sum:2 [(4-3)+(2(final_default)-1)=1+1]
3,
1
],
"final_default": [
2
]
}
]
},
{
"key": "TP-2",
"status_map": [
{
"status": "Closed",
"final": [
1,
5
], // Expected Output
"start": [], //sum:4 [(1-1(start_default))+(5-1(start_default))=0+4]
"final_default": [
3
]
},
{
"status": "Done",
"final": [], // Expected Output
"start": [ //sum:3 [(5(final_default)-3)+(5(final_default)-4)=2+1]
3,
4
],
"final_default": [
5
]
}
]
}
]
}
假设 start_default
值 = 1
,这是我的预期输出
{
"data": [
{
"key": "TP-1",
"status_map": [
{
"status": "Closed",
"sum": 6 //[(6-2)+(3-1(start_default))=4+2]
{
"status": "Done",
"sum": 2 //[(4-3)+(2(final_default)-1)=1+1]
}
]
},
{
"key": "TP-2",
"status_map": [
{
"status": "Closed",
"sum": 4 //[(1-1(start_default))+(5-1(start_default))=0+4]
},
{
"status": "Done",
"sum": 3 //[(5(final_default)-3)+(5(final_default)-4)=2+1]
}
]
}
]
}
如何实现这个用例?
您可以从双 $map to rewrite your nested array. You'll also need $reduce since you'll be converting an array into scalar value. Since you need to "pair" two arrays, there's a perfect operator called $zip 开始,即使数组长度不同也可以使用。为第一个子文档配对 final
和 start
将 return:
[ [ 6,2 ], [ 3, null ] ]
这很棒,因为您可以使用 $ifNull 提供默认值。
您的汇总如下所示:
db.collection.aggregate([
{
$project: {
data: {
$map: {
input: "$data",
as: "d",
in: {
key: "$$d.key",
status_map: {
$map: {
input: "$$d.status_map",
as: "sm",
in: {
status: "$$sm.status",
sum: {
$reduce: {
input: {
$zip: {
inputs: [ "$$sm.final", "$$sm.start" ],
useLongestLength: true
}
},
initialValue: 0,
in: {
$add: [
"$$value",
{
$subtract: [
{ $ifNull: [ { $arrayElemAt: [ "$$this", 0 ] }, { $arrayElemAt: [ "$$sm.final_default" , 0] } ] },
{ $ifNull: [ { $arrayElemAt: [ "$$this", 1 ] }, 1 ] }
]
}
]
}
}
}
}
}
}
}
}
}
}
}
])
我正在尝试从聚合管道中的 final
数组和 start
数组中减去值。但也有一些特殊情况需要在减法之前添加一些额外的逻辑。
预期输出:
- I need to subtract nth value of
start
array from nth value offinal
array- And then, get the total sum of subtracted values
特殊情况:
- If nth value of
start
array is NULL, use a start_default value(from the query)- If nth value of
final
array is NULL, use value from thefinal_default
array
经过一些聚合阶段后,我的 MongoDB 文档具有以下格式:
Assuming that start_default value = 1
I have commented the way I expect to perform subtractions in each of the group
{
"data": [
{
"key": "TP-1",
"status_map": [
{
"status": "Closed",
"final": [
6,
3
], // Expected Output
"start": [ // sum:6 [(6-2)+(3-1(start_default))=4+2]
2
],
"final_default": [
4
]
},
{
"status": "Done",
"final": [
4
], // Expected Output
"start": [ // sum:2 [(4-3)+(2(final_default)-1)=1+1]
3,
1
],
"final_default": [
2
]
}
]
},
{
"key": "TP-2",
"status_map": [
{
"status": "Closed",
"final": [
1,
5
], // Expected Output
"start": [], //sum:4 [(1-1(start_default))+(5-1(start_default))=0+4]
"final_default": [
3
]
},
{
"status": "Done",
"final": [], // Expected Output
"start": [ //sum:3 [(5(final_default)-3)+(5(final_default)-4)=2+1]
3,
4
],
"final_default": [
5
]
}
]
}
]
}
假设 start_default
值 = 1
{
"data": [
{
"key": "TP-1",
"status_map": [
{
"status": "Closed",
"sum": 6 //[(6-2)+(3-1(start_default))=4+2]
{
"status": "Done",
"sum": 2 //[(4-3)+(2(final_default)-1)=1+1]
}
]
},
{
"key": "TP-2",
"status_map": [
{
"status": "Closed",
"sum": 4 //[(1-1(start_default))+(5-1(start_default))=0+4]
},
{
"status": "Done",
"sum": 3 //[(5(final_default)-3)+(5(final_default)-4)=2+1]
}
]
}
]
}
如何实现这个用例?
您可以从双 $map to rewrite your nested array. You'll also need $reduce since you'll be converting an array into scalar value. Since you need to "pair" two arrays, there's a perfect operator called $zip 开始,即使数组长度不同也可以使用。为第一个子文档配对 final
和 start
将 return:
[ [ 6,2 ], [ 3, null ] ]
这很棒,因为您可以使用 $ifNull 提供默认值。
您的汇总如下所示:
db.collection.aggregate([
{
$project: {
data: {
$map: {
input: "$data",
as: "d",
in: {
key: "$$d.key",
status_map: {
$map: {
input: "$$d.status_map",
as: "sm",
in: {
status: "$$sm.status",
sum: {
$reduce: {
input: {
$zip: {
inputs: [ "$$sm.final", "$$sm.start" ],
useLongestLength: true
}
},
initialValue: 0,
in: {
$add: [
"$$value",
{
$subtract: [
{ $ifNull: [ { $arrayElemAt: [ "$$this", 0 ] }, { $arrayElemAt: [ "$$sm.final_default" , 0] } ] },
{ $ifNull: [ { $arrayElemAt: [ "$$this", 1 ] }, 1 ] }
]
}
]
}
}
}
}
}
}
}
}
}
}
}
])