C++ 20 概念:需要运算符重载
C++ 20 Concepts: Require operator overloading
我正在尝试了解如何声明一个概念,该概念要求特定运算符针对给定类型重载。假设我有以下函数,它接受任意类型的向量并将其打印到 std::cout
:
template<typename printable>
void print_vector(const std::vector<printable>& vec)
{
std::cout << '{';
for (const printable &item : vec) {
std::cout << item << ',';
}
std::cout << '}';
}
如果类型 printable
具有重载的 <<
运算符,此代码将正常工作,但如果没有,则它会失败并出现一个非常无用的编译器错误。我觉得我应该能够以某种方式声明一个概念,该概念需要一个定义了有效 <<
运算符的类型,并在函数声明中使用该概念,以便我可以获得更有用的编译器错误,但我还没有还没想好怎么做。
template <class T>
concept Printable = requires(std::ostream& os, T a)
{
os << a;
};
template<Printable T>
void print_vector(const std::vector<T>& vec) {
std::cout << '{';
for (const auto &item : vec) {
std::cout << item << ',';
}
std::cout << '}';
}
如果您愿意,还可以使其更通用以对 basic_ostream
进行操作。
这是 clang 错误消息:
<source>:30:5: error: no matching function for call to 'print_vector'
print_vector(x);
^~~~~~~~~~~~
<source>:19:6: note: candidate template ignored: constraints not satisfied [with T = X]
void print_vector(std::vector<T> vec) {
^
<source>:18:10: note: because 'X' does not satisfy 'Printable'
template<Printable T>
^
<source>:10:9: note: because 'os << a' would be invalid: invalid operands to binary expression ('std::ostream' (aka 'basic_ostream<char>') and 'X')
os << a;
^
和 gcc:
<source>: In function 'auto test()':
<source>:30:19: error: use of function 'void print_vector(std::vector<T>) [with T = X]' with unsatisfied constraints
30 | print_vector(x);
| ^
<source>:19:6: note: declared here
19 | void print_vector(std::vector<T> vec) {
| ^~~~~~~~~~~~
<source>:19:6: note: constraints not satisfied
<source>: In instantiation of 'void print_vector(std::vector<T>) [with T = X]':
<source>:30:19: required from here
<source>:8:9: required for the satisfaction of 'Printable<T>' [with T = X]
<source>:8:21: in requirements with 'std::ostream& os', 'T a' [with T = X]
<source>:10:9: note: the required expression '(os << a)' is invalid
10 | os << a;
| ~~~^~~~
cc1plus: note: set '-fconcepts-diagnostics-depth=' to at least 2 for more detail
我正在尝试了解如何声明一个概念,该概念要求特定运算符针对给定类型重载。假设我有以下函数,它接受任意类型的向量并将其打印到 std::cout
:
template<typename printable>
void print_vector(const std::vector<printable>& vec)
{
std::cout << '{';
for (const printable &item : vec) {
std::cout << item << ',';
}
std::cout << '}';
}
如果类型 printable
具有重载的 <<
运算符,此代码将正常工作,但如果没有,则它会失败并出现一个非常无用的编译器错误。我觉得我应该能够以某种方式声明一个概念,该概念需要一个定义了有效 <<
运算符的类型,并在函数声明中使用该概念,以便我可以获得更有用的编译器错误,但我还没有还没想好怎么做。
template <class T>
concept Printable = requires(std::ostream& os, T a)
{
os << a;
};
template<Printable T>
void print_vector(const std::vector<T>& vec) {
std::cout << '{';
for (const auto &item : vec) {
std::cout << item << ',';
}
std::cout << '}';
}
如果您愿意,还可以使其更通用以对 basic_ostream
进行操作。
这是 clang 错误消息:
<source>:30:5: error: no matching function for call to 'print_vector' print_vector(x); ^~~~~~~~~~~~ <source>:19:6: note: candidate template ignored: constraints not satisfied [with T = X] void print_vector(std::vector<T> vec) { ^ <source>:18:10: note: because 'X' does not satisfy 'Printable' template<Printable T> ^ <source>:10:9: note: because 'os << a' would be invalid: invalid operands to binary expression ('std::ostream' (aka 'basic_ostream<char>') and 'X') os << a; ^
和 gcc:
<source>: In function 'auto test()': <source>:30:19: error: use of function 'void print_vector(std::vector<T>) [with T = X]' with unsatisfied constraints 30 | print_vector(x); | ^ <source>:19:6: note: declared here 19 | void print_vector(std::vector<T> vec) { | ^~~~~~~~~~~~ <source>:19:6: note: constraints not satisfied <source>: In instantiation of 'void print_vector(std::vector<T>) [with T = X]': <source>:30:19: required from here <source>:8:9: required for the satisfaction of 'Printable<T>' [with T = X] <source>:8:21: in requirements with 'std::ostream& os', 'T a' [with T = X] <source>:10:9: note: the required expression '(os << a)' is invalid 10 | os << a; | ~~~^~~~ cc1plus: note: set '-fconcepts-diagnostics-depth=' to at least 2 for more detail