在 SQL 服务器中创建日历 table
Create calendar table in SQL Server
我正在使用 Microsoft SQL Server 2012,我正在创建以下 table:
Clinic_code Clinic_name D D_days_passed
------------------------------------------------------
A123 NAME1 2018-12-01 1
A124 NAME2 2018-12-01 1
A125 NAME3 2018-12-01 1
[...]
A123 NAME1 2018-12-02 2
A124 NAME2 2018-12-02 2
A125 NAME3 2018-12-02 2
[...]
A123 NAME1 2018-12-03 3
A124 NAME2 2018-12-03 3
A125 NAME3 2018-12-03 3
我在这里改编了来自@JohnCappelletti 的代码,但我正在努力包含 'D_days_passed' 列,该列主要计算自 Start_date:
以来的天数
DECLARE @fromdate date = '2018-12-01'
SELECT #MyTable.*, B.D
FROM #MyTable
CROSS APPLY
(SELECT TOP (DATEDIFF(DAY, @fromdate, DATEADD(Month, 9, @fromdate)) + 1)
D = CONVERT(date, DATEADD(DAY, -1 + ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), @fromdate))
FROM master..spt_values n1) B
有空的话
问题:如何将代码调整为,而不是包括每个诊所从一个日期到另一个日期的每一天,我想为每个诊所引入同一周的时间段,例如如此,周六至周日:
Clinic_code Clinic_name D_start D_end Weeks_passed
-------------------------------------------------------------------------
A123 NAME1 2018-12-02 2018-12-08 1
A124 NAME2 2018-12-02 2018-12-08 1
A125 NAME3 2018-12-02 2018-12-08 1
[...]
A123 NAME1 2018-12-09 2018-12-15 2
A124 NAME2 2018-12-09 2018-12-15 2
A125 NAME3 2018-12-09 2018-12-15 2
[...]
A123 NAME1 2018-12-16 2018-12-22 3
A124 NAME2 2018-12-16 2018-12-22 3
A125 NAME3 2018-12-16 2018-12-22 3
您可以只使用 window 函数获取最早日期,然后 datediff()
:
Select t.*, B.D,
datediff(day, min(date) over (), date) + 1 as days_passed
From #MyTable t Cross Apply
(Select Top (DateDiff(DAY,@fromdate,DateAdd(Month,9,@fromdate))+1)
D=convert(date,DateAdd(DAY,-1+Row_Number() Over (Order By (Select Null)),@fromdate))
From master..spt_values n1
) B;
这也应该可以工作数周。
我正在使用 Microsoft SQL Server 2012,我正在创建以下 table:
Clinic_code Clinic_name D D_days_passed
------------------------------------------------------
A123 NAME1 2018-12-01 1
A124 NAME2 2018-12-01 1
A125 NAME3 2018-12-01 1
[...]
A123 NAME1 2018-12-02 2
A124 NAME2 2018-12-02 2
A125 NAME3 2018-12-02 2
[...]
A123 NAME1 2018-12-03 3
A124 NAME2 2018-12-03 3
A125 NAME3 2018-12-03 3
我在这里改编了来自@JohnCappelletti 的代码,但我正在努力包含 'D_days_passed' 列,该列主要计算自 Start_date:
以来的天数DECLARE @fromdate date = '2018-12-01'
SELECT #MyTable.*, B.D
FROM #MyTable
CROSS APPLY
(SELECT TOP (DATEDIFF(DAY, @fromdate, DATEADD(Month, 9, @fromdate)) + 1)
D = CONVERT(date, DATEADD(DAY, -1 + ROW_NUMBER() OVER (ORDER BY (SELECT NULL)), @fromdate))
FROM master..spt_values n1) B
有空的话
问题:如何将代码调整为,而不是包括每个诊所从一个日期到另一个日期的每一天,我想为每个诊所引入同一周的时间段,例如如此,周六至周日:
Clinic_code Clinic_name D_start D_end Weeks_passed
-------------------------------------------------------------------------
A123 NAME1 2018-12-02 2018-12-08 1
A124 NAME2 2018-12-02 2018-12-08 1
A125 NAME3 2018-12-02 2018-12-08 1
[...]
A123 NAME1 2018-12-09 2018-12-15 2
A124 NAME2 2018-12-09 2018-12-15 2
A125 NAME3 2018-12-09 2018-12-15 2
[...]
A123 NAME1 2018-12-16 2018-12-22 3
A124 NAME2 2018-12-16 2018-12-22 3
A125 NAME3 2018-12-16 2018-12-22 3
您可以只使用 window 函数获取最早日期,然后 datediff()
:
Select t.*, B.D,
datediff(day, min(date) over (), date) + 1 as days_passed
From #MyTable t Cross Apply
(Select Top (DateDiff(DAY,@fromdate,DateAdd(Month,9,@fromdate))+1)
D=convert(date,DateAdd(DAY,-1+Row_Number() Over (Order By (Select Null)),@fromdate))
From master..spt_values n1
) B;
这也应该可以工作数周。