在 Scala 中编写状态 monad

Programming a state monad in Scala

我从 Philip Wadler 的 Monads for Functional Programming 借来的关于状态 monad 的理论:

type M a = State → (a, State) 
type State = Int
unit :: a → M a
unit a = λx. (a, x)
(*) :: M a → (a → M b) → M b
m * k = λx. 
         let (a, y) = m x in 
         let (b, z) = k a y in 
         (b, z)

我想使用状态 monad 的方式如下:

Given a list L I want different parts of my code to get this list and update this list by adding new elements at its end.

我猜上面会被修改为:

type M = State → (List[Data], State) 
type State = List[Data]
def unit(a: List[Data]) = (x: State) => (a,x)
def star(m: M, k: List[Data] => M): M = {
 (x: M) => 
   val (a,y) = m(x)
   val (b,z) = k(a)(y)
   (b,z)
} 
def get = ???
def update = ???

如何填写详细信息,即?

  1. 如何实例化我的层次结构以处理具体列表?
  2. 如何实现上面的get和update?

最后,我如何使用 Scala 的 flatMap 和 unit 语法来做到这一点?

您的 M 定义不正确。它应该以 a/A 作为参数,像这样:

type M[A] = State => (A, State)

您在其他地方也遗漏了该类型参数。

unit 应该有这样的签名:

def unit[A](a: A): M[A]

star 应该有这样的签名:

def star[A, B](m: M[A], k: A => M[B]): M[B]

希望这样可以使功能更加清晰。

您对 unit 的实施几乎相同:

def unit[A](a: A): M[A] = x => (a, x)

但是,在star中,你的lambda(x)的参数是State类型,而不是M,因为M[B]基本上是State => (A, State)。剩下的你答对了:

def star[A, B](m: M[A])(k: A => M[B]): M[B] = 
  (x: State) => {
    val (a, y) = m(x)
    val (b, z) = k(a)(y)
    (b, z)
  }

编辑:根据@Luis Miguel Mejia Suarez 的说法:

It would probably be easier to implement if you make your State a class and define flatMap inside it. And you can define unit in the companion object.

他建议 final class State[S, A](val run: S => (A, S)),这也允许您使用像 >>=.

这样的中缀函数

另一种方法是将 State 定义为函数 S => (A, S) 的类型别名,并使用隐式 class.

对其进行扩展
type State[S, A] = S => (A, S)
object State {
  //This is basically "return"
  def unit[S, A](a: A): State[S, A] = s => (a, s)
}

implicit class StateOps[S, A](private runState: S => (A, S)) {
  //You can rename this to ">>=" or "flatMap"
  def *[B](k: A => State[S, B]): State[S, B] = s => {
    val (a, s2) = runState(s)
    k(a)(s2)
  }
}

如果你对get的定义是

set the result value to the state and leave the state unchanged (borrowed from Haskell Wiki), then you can implement it like this:

def get[S]: State[S, S] = s => (s, s)

如果你的意思是要提取状态(在本例中是List[Data]),你可以使用execState(在StateOps中定义):

def execState(s: S): S = runState(s)._2

这是一个糟糕的例子,说明如何将元素添加到 List

def addToList(n: Int)(list: List[Int]): ((), List[Int]) = ((), n :: list)

def fillList(n: Int): State[List[Int], ()] =
  n match {
    case 0 => s => ((), s)
    case n => fillList(n - 1) * (_ => addToList(n))
  }

println(fillList(10)(List.empty)) 给了我们这个(第二个元素可以用 execState 提取):

((),List(10, 9, 8, 7, 6, 5, 4, 3, 2, 1))