我需要一个更好的方法来编写这个随机字母生成器

Question

通过反复试验，我最终解决了这个问题，请帮助我。一个随机生成器，为文本框生成 5 个随机字母，所有字母都必须有自己的随机机会。我正在寻找一种更简洁的方式来编写这个随机字母生成器。也许使用 Random() 的不同方式。

       private void GenerateLetter_Click(object sender, EventArgs e)
    {       Random rnd = new Random(); 
            String[] rArray = { "A", "B", "C", "D", "E", "F", "G" };            
            int x1 = rnd.Next(0,7);
            int x2 = rnd.Next(0, 7);
            int x3 = rnd.Next(0, 7);
            int x5 = rnd.Next(0, 7);
            int x6 = rnd.Next(0, 7);
            int x7 = rnd.Next(0, 7);
            int x8 = rnd.Next(0, 7);
            int x9 = rnd.Next(0, 7);
            int x10 = rnd.Next(0, 7);
            int x11 = rnd.Next(0, 7);
            int x12 = rnd.Next(0, 7);
            int x13 = rnd.Next(0, 7);
            int x14 = rnd.Next(0, 7);
            int x15 = rnd.Next(0, 7);
            int x16 = rnd.Next(0, 7);
            int x17 = rnd.Next(0, 7);
            int x18 = rnd.Next(0, 7);
            int x19 = rnd.Next(0, 7);
            int x20 = rnd.Next(0, 7);

            textBox1.Text =  rArray[x1] + rArray[x2] + rArray[x3] + rArray[x4] + rArray[x5];
            textBox2.Text =  rArray[x6] + rArray[x7] + rArray[x8] + rArray[x9] + rArray[x10];
            textBox3.Text =  rArray[x11] + rArray[x12] + rArray[x13] + rArray[x14] + rArray[x15];
            textBox4.Text =  rArray[x16] + rArray[x17] + rArray[x18] + rArray[x19] + rArray[x20];            
    }

Answer 1

static readonly Random Rand = new Random();
private const string Alpha = "ABCDEFG";

 public static string GenerateAlphaString(int size)
        {
            var chars = new char[size];
            for (int i = 0; i < size; i++)
            {
                chars[i] = Alpha[Rand.Next(Alpha.Length)];
            }
            return new string(chars);
        }

然后调用该方法：

textBox1.Text = GenerateAlphaString(5);

Answer 2

给你一个随机字母的静态方法：

using System;

static class RandomLetter
{
    static Random _random = new Random();
    public static char GetLetter()
    {
    int num = _random.Next(0, 26); // Zero to 25
    char let = (char)('a' + num);
    return let;
    }
}

使用：

Console.WriteLine(RandomLetter.GetLetter());

Answer 3

此代码与您提供的代码完全相同：

private static Random rand = new Random();
private static string alphabet = "ABCDEFG";
private static string GetRandomString(int length)
{
    var stringBuilder = new StringBuilder();
    for (int i = 0; i < length; i++)
    {
        stringBuilder.Append(alphabet[rand.Next(0, alphabet.length)]);
    }
    return stringBuilder.ToString();
}

private void GenerateLetter_Click(object sender, EventArgs e)
{
    textBox1.Text = GetRandomString(5);
    textBox2.Text = GetRandomString(5);
    textBox3.Text = GetRandomString(5);
    textBox4.Text = GetRandomString(5);         
}

我需要一个更好的方法来编写这个随机字母生成器

I need a better way to code this Random Letter generator

c#

random