php 移动脚本路径后，扫描功能未按预期返回结果：

Question

注意.. 所有文件夹 chmod 设置为 777 进行测试。

好的，所以我一直在尝试设计一个简单的云存储文件系统，在 php.After 用户登录后，他们可以上传和浏览他们帐户中的文件。

我的 php 扫描用户存储区域的代码有问题。我有一个名为 scan.php 的脚本，它会调用 return 他们保存的所有用户文件和文件夹。

我最初将扫描脚本放在名为 files 的目录中并且它工作正常，当用户登录时扫描脚本使用 "scan(files/usernamevalue)" 扫描了用户文件。

但是我决定我更愿意将扫描脚本移动到文件区域内，这样 php 脚本只需使用 "scan(usernamevalue)" 调用扫描。但是现在我的脚本没有 return 用户文件和文件夹。

<?php
session_start();
$userfileloc = $_SESSION["activeuser"];
$dir = $userfileloc;
// Run the recursive function 

$response = scan($dir);


// This function scans the files folder recursively, and builds a large array

function scan($dir)
{
 
 
 $files = array();

 // Is there actually such a folder/file?
 $i=0;
 if(file_exists($dir))
 {
  
  foreach(scandir($dir) as $f) 
  {
  
   if(!$f || $f[0] === '.') 
   {
    continue; // Ignore hidden files
   }
   

   
   
   if(!is_dir($dir . '/' . $f)) 
   {
    // It is a file

    $files[] = array
    (
     "name" => $f,
     "type" => "file",
     "path" => $dir . '/' . $f,
     "size" => filesize($dir . '/' . $f) // Gets the size of this file
    );
    //testing that code actually finding files
    echo "type = file, ";
    echo $f .", ";
    echo $dir . '/' . $f. ", ";
    echo filesize($dir . '/' . $f)." ";
    echo"\n";
   }   
   else 
   {

    
    // The path is a folder

    $files[] = array
    (    
     "name" => $f,
     "type" => "folder",
     "path" => $dir . '/' . $f,
     "items" => scan($dir . '/' . $f) // Recursively get the contents of the folder
    );
    
    //testing that code actually finding files
    echo "type = folder, ";
    echo $f .", ";
    echo $dir . '/' . $f. ", ";
    echo filesize($dir . '/' . $f)." ";
    echo"\n";
   }
   
   
  }
 
 }
 else
 {
  echo "dir does not exist";
 }
 
}



// Output the directory listing as JSON
if(!$response)
{ echo"failes to respond \n";}


header('Content-type: application/json');
echo json_encode(array(
 "name" => $userfileloc,
 "type" => "folder",
 "path" => $dire,
 "items" => $response
));
?>

As you can see i added i echoed out all of the results to see if there was any error in the scan process, here is what i get from the output as you can see the function returns null, but the files are being scanned, i cant seem to figure out where i am going wrong. Your help would be greatly appreciated. Thank you.

type = file, HotAirBalloonDash.png, test/HotAirBalloonDash.png, 658616

type = folder, New directory, test/New directory, 4096

type = file, Transparent.png, test/Transparent.png, 213

failes to respond

{"name":"test","type":"folder","path":null,"items":null}

Answer 1

您忘记在 scan 函数中 return 文件或文件夹，只是回显值。这就是为什么您在响应中得到 null 值的原因。

可能的解决方案是在所有情况下 return $files 变量。

php 移动脚本路径后，扫描功能未按预期返回结果：

php Scan function not returning results as expected after moving script path:

php

server-side

scandir