在下一个数组中查找要替换的对象数组

Question

我有两个下面的数组对象。我想找到第一个数组的所有这些 ID，并使它们在第二个对象数组中处于活动状态，其余的必须在状态属性中变为 none。

var searchIDs = [{ "id":"6001", "other" : "..." }, 
{ "id":"6002", "other" : "..."}] 

var list = [ 
    {"id":"9666", "status":"active"},
    {"id":"9667", "status":"none"},
    {"id":"9999", "status":"none"},
    {"id":"9668", "status":"none"},
    {"id":"9669", "status":"active"},
    {"id":"6001", "status":"none"},
    {"id":"6002", "status":"none"},
    {"id":"6003", "status":"none"},
    {"id":"6004", "status":"none"},
    {"id":"6005", "status":"active"},
    {"id":"6006", "status":"none"},
    {"id":"6007",  "status":"none"},
    {"id":"6008",  "status":"none"},
    {"id":"6009",  "status":"none"}
]



for (var i = 0 ; i < searchIDs.length ; i ++) {

    list.find(v => v.id !== searchIDs[i].id).status = "none";
    list.find(v => v.id === searchIDs[i].id).status = "active";
    Array.prototype.push.apply(list); 


}



console.log('Final List : '  + JSON.stringify(list));

但是当我尝试使用带有 for 循环的 find 函数时，它暂时不起作用。我该如何解决？感谢阅读我的问题！谢谢！

最终结果应该是


[ 
    {"id":"9666", "status":"none"},
    {"id":"9667", "status":"none"},
    {"id":"9999", "status":"none"},
    {"id":"9668", "status":"none"},
    {"id":"9669", "status":"none"},
    {"id":"6001", "status":"active"},
    {"id":"6002", "status":"active"},
    {"id":"6003", "status":"none"},
    {"id":"6004", "status":"none"},
    {"id":"6005", "status":"none"},
    {"id":"6006", "status":"none"},
    {"id":"6007",  "status":"none"},
    {"id":"6008",  "status":"none"},
    {"id":"6009",  "status":"none"}
]

Answer 1

我建议在对第二个列表 (list) 的 Array.map 调用中搜索第一个列表 (searchIDs) 中的项目，我们实质上是在检查列表的每个成员是否也是searchIDs.

如果 searchIDs 非常大，这可能不是非常有效，因此可以创建一个 Set and check for membership using Set.has。

var searchIDs = [{ "id":"6001", "other" : "..." }, 
{ "id":"6002", "other" : "..."}] 

var list = [ 
    {"id":"9666", "status":"active"},
    {"id":"9667", "status":"none"},
    {"id":"9999", "status":"none"},
    {"id":"9668", "status":"none"},
    {"id":"9669", "status":"active"},
    {"id":"6001", "status":"none"},
    {"id":"6002", "status":"none"},
    {"id":"6003", "status":"none"},
    {"id":"6004", "status":"none"},
    {"id":"6005", "status":"active"},
    {"id":"6006", "status":"none"},
    {"id":"6007",  "status":"none"},
    {"id":"6008",  "status":"none"},
    {"id":"6009",  "status":"none"}
]


list = list.map(r => { 
    return { id: r.id, status: searchIDs.find(s => s.id === r.id) ? "active": "none" };
})

console.log(list);

Answer 2

这有效。

  var searchIDs = [
   { "id":"6001", "other" : "..." }, 
   { "id":"6002", "other" : "..."}
  ] 
  var list = [ 
    {"id":"9666", "status":"active"},
    {"id":"9667", "status":"none"},
    {"id":"9999", "status":"none"},
    {"id":"9668", "status":"none"},
    {"id":"9669", "status":"active"},
    {"id":"6001", "status":"none"},
    {"id":"6002", "status":"none"},
    {"id":"6003", "status":"none"},
    {"id":"6004", "status":"none"},
    {"id":"6005", "status":"active"},
    {"id":"6006", "status":"none"},
    {"id":"6007",  "status":"none"},
    {"id":"6008",  "status":"none"},
    {"id":"6009",  "status":"none"}
  ]

  let resArr =  list.map(function(item){
     let obj = item;
     if(searchIDs.find(x => x.id == item.id)){
       obj.status = "active";
     }else{
       obj.status = "none";
     }
     return obj;
  });
  console.log(resArr);

Answer 3

如果我理解正确的话。这可能就是您要找的

var searchIDs = [
    { "id":"6001", "other" : "..." }, 
    { "id":"6002", "other" : "..."}
] 

var list = [ 
    {"id":"9666", "status":"active"},
    {"id":"9667", "status":"none"},
    {"id":"9999", "status":"none"},
    {"id":"9668", "status":"none"},
    {"id":"9669", "status":"active"},
    {"id":"6001", "status":"none"},
    {"id":"6002", "status":"none"},
    {"id":"6003", "status":"none"},
    {"id":"6004", "status":"none"},
    {"id":"6005", "status":"active"},
    {"id":"6006", "status":"none"},
    {"id":"6007",  "status":"none"},
    {"id":"6008",  "status":"none"},
    {"id":"6009",  "status":"none"}
]

// This line creates a new array with only the id's in it
const ids = searchIDs.map(line => line.id)


// We will map this array
// if the this line id appears in the ids list we can set the status to active. otherwise to none
var newList = list.map(line => {
  // you could also use .includes
  line.status = ids.indexOf(line.id) > -1 ? 'active' : 'none';
  return line;
})

console.log(newList)

Answer 4

下面是一个非常基本的方法，希望对您有所帮助。

var searchIDs = [{ "id":"6001", "other" : "..." }, 
    { "id":"6002", "other" : "..."}] 
    
    var list = [ 
        {"id":"9666", "status":"active"},
        {"id":"9667", "status":"none"},
        {"id":"9999", "status":"none"},
        {"id":"9668", "status":"none"},
        {"id":"9669", "status":"active"},
        {"id":"6001", "status":"none"},
        {"id":"6002", "status":"none"},
        {"id":"6003", "status":"none"},
        {"id":"6004", "status":"none"},
        {"id":"6005", "status":"active"},
        {"id":"6006", "status":"none"},
        {"id":"6007",  "status":"none"},
        {"id":"6008",  "status":"none"},
        {"id":"6009",  "status":"none"}
    ]
    
    let newsearchIds = [];
    
    for (var i = 0 ; i < searchIDs.length ; i ++) {
        for(let key in searchIDs[i]){
            newsearchIds.push(searchIDs[i][key]);
        }
    }
    
    for (var i = 0 ; i < list.length ; i ++) {
        for (var j = 0 ; j < newsearchIds.length ; j ++) {
            if(list[i].id === newsearchIds[j]){
                list[i].status= "active";
            }
        }
    }
    console.log(list);

在下一个数组中查找要替换的对象数组

Find array of objects in next array to replace

javascript

arrays

arrayobject