如何获得完整的解释器启动横幅

Question

我正在尝试获取 Python 中的启动横幅信息，而不仅仅是：

f'''Python {sys.version} on {sys.platform}
Type "help", "copyright", "credits", or "license" for more information.'''

这导致：

Python 3.8.3 (default, Jul 2 2020, 17:30:36) [MSC v.1916 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.

但完整的启动横幅包括任何错误和分发，例如：

Python 3.8.3 (default, Jul  2 2020, 17:30:36) [MSC v.1916 64 bit (AMD64)] :: Anaconda, Inc. on win32

Warning:
This Python interpreter is in a conda environment, but the environment has
not been activated. Libraries may fail to load. To activate this environment
please see https://conda.io/activation.

Type "help", "copyright", "credits" or "license" for more information.

本来想在subprocess.Popen中运行python然后终止它，但是一直没能捕捉到启动横幅输出

Answer 1

我终于弄明白了这个问题。结果 subprocess.Popen 是正确答案。有趣的是 header 被打印成 stderr 而不是 stdout。对我有用的代码：

from subprocess import (Popen, PIPE)
from os import devnull
from sys import executable
from time import sleep
nump = open(devnull, 'w+') #Making a dud file so the stdin won't be the same as the main interpreter
hed = Popen(executable, shell=True, stdout=PIPE, stderr=PIPE, stdin=nump)
sleep(0.1) #Sleeping so python has time to print the header before we kill it
hed.terminate()
nump.close()
print(hed.stderr.read().decode('utf-8').strip().strip('>>>').strip()) #Removing whitespace and the '>>>'

如何获得完整的解释器启动横幅

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