Pynput 按键延迟和 Tkinter

Question

我只是想制作一个程序来执行一些键盘输入。我想在每次击键之间设置一个延迟，我计划在将来随机设置。

但是，我不确定如何将 after() 与 Tkinter 一起使用。没有 Tkinter，time.sleep 工作正常 - 但有了它，GUI 崩溃。

如有任何帮助，我们将不胜感激。

import time
import tkinter as tk
from pynput.keyboard import Key, Controller as KeyboardController
from pynput.mouse import Button, Controller as MouseController

keyboard = KeyboardController()
mouse = MouseController()



def copy(a):
    pause_input=17
    pause_input2=2
    pause_input3=0.5
    x=1
    while a >= x:
        x = x+1
        time.sleep(pause_input)
        keyboard.press('t')
        keyboard.release('t')
        time.sleep(pause_input3)
        keyboard.press('e')
        keyboard.release('e')
        time.sleep(pause_input3)
        keyboard.press('s')
        keyboard.release('s')
        keyboard.press('t')
        keyboard.release('t')
        
root = tk.Tk()
root.title("GUI Button")
btn1 = tk.Button(root, text="Button 1", command=lambda : copy(360))
btn2 = tk.Button(root, text="Button 2")

btn1.pack()
btn2.pack()


root.mainloop()

Answer 1

首先：gui 不会崩溃 - 它工作正常并且在主循环中它执行您正在编写的命令。它不刷新，因为它打印输出而不是刷新 UI。首先注意在创建 UI 时需要记住的是，您应该省略主线程中不必要的工作。可能的解决方案：将工作移至单独的线程并运行在那里，例如：

import time
import tkinter as tk
from pynput.keyboard import Controller as KeyboardController
import threading

keyboard = KeyboardController()

def copy(a):

    def print_test(a):
        pause_input=2
        pause_input2=2
        pause_input3=0.5
        for _ in range(a):
            time.sleep(pause_input)
            keyboard.press('t')
            keyboard.release('t')
            time.sleep(pause_input3)
            keyboard.press('e')
            keyboard.release('e')
            time.sleep(pause_input3)
            keyboard.press('s')
            keyboard.release('s')
            keyboard.press('t')
            keyboard.release('t')
            print("Wrote test")

    t = threading.Thread(target=print_test, args=(a,))
    t.start()
        
root = tk.Tk()
root.title("GUI Button")
btn1 = tk.Button(root, text="Button 1", command=lambda : copy(360))

btn1.pack()

root.mainloop()

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