在 Makefile 中使用条件运算符比较两个变量

Question

下面是我的 Makefile。我只想使用 && 运算符（或等效运算符）进行比较如下图pseudocode.I想运行下面逻辑里面的“全部”target

#   if (CUR_PI_VERSION == LAST_PI_VERSION) && (CUR_GIT_VERSION == LAST_GIT_VERSION) 
#       print "everything matched. Nothing to do"
#   else
#       print "files not matched"
#       run python script.
#
#   How do I achieve this.

我看了其他的答案，但得不到我想要的结果。我已附上我的示例代码以供参考。

CUR_PI_VERSION:= "abc"
CUR_GIT_VERSION:= "cde"

LAST_PI_VERSION:= "abc"
LAST_GIT_VERSION:= "cde"

$(info $$CUR_GIT_VERSION is [${CUR_GIT_VERSION}])
$(info $$CUR_PI_VERSION is [${CUR_PI_VERSION}])

$(info $$LAST_GIT_VERSION is [${LAST_GIT_VERSION}])
$(info $$LAST_PI_VERSION is [${LAST_PI_VERSION}])

all:

# The pseudocode of what I want to do is as follows 
#   if (CUR_PI_VERSION == LAST_PI_VERSION) && (CUR_GIT_VERSION == LAST_GIT_VERSION) 
#       print "everything matched. Nothing to do"
#   else
#       print "files not matched"
#       run python script.
#
#   How do I achieve this.
#
    ifeq ($(CUR_GIT_VERSION),$(LAST_GIT_VERSION))
        ifeq ($(CUR_FPI_VERSION),$(LAST_FPI_VERSION))
            echo "Everything matched, so don't need the make top"
        endif 
    endif

非常感谢任何帮助。

Answer 1

你可以试试这个：

all:
ifeq ($(CUR_PI_VERSION)@$(CUR_GIT_VERSION),$(LAST_PI_VERSION)@$(LAST_GIT_VERSION))
    echo "Everything matched, so don't need the make top"
endif

以上测试比较了两个连接的字符串（由 @ 连接）：

$(CUR_PI_VERSION)@$(CUR_GIT_VERSION)

和

$(LAST_PI_VERSION)@$(LAST_GIT_VERSION)

在 Makefile 中使用条件运算符比较两个变量

comparing two variables using condition operator in Makefiles

linux

makefile

comparison-operators