如何加入多个mp3文件？

Question

阅读其他问题我想知道如何加入多个 mp3 文件。我尝试了这段代码，但我得到的输出只是 output.mp3 中的 2 个最新的 mp3 文件...预期的输出应该是将所有文件放入 1 个 mp3 文件中。

from pydub import AudioSegment
from os import getcwd
import glob

cwd = (getcwd()).replace(chr(92), '/')
export_path = f'{cwd}/result.mp3'

MP3_FILES = glob.glob(pathname=f'{cwd}/*.mp3', recursive=True)
silence = AudioSegment.silent(duration=15000)
count, lenght = 0, len(MP3_FILES)

for n, mp3_file in enumerate(MP3_FILES):
    mp3_file = mp3_file.replace(chr(92), '/')
    print(n, mp3_file)

    count += 1
    if count == 1:
        # We get here upon fetching the first audio file from the list.
        # So we load it into `audio1`
        audio1 = AudioSegment.from_mp3(mp3_file)
        print('audio1')

    elif count == 2:
        # We get here upon fetching the second audio file from the list.
        # So we load it into `audio2`
        audio2 = AudioSegment.from_mp3(mp3_file)
        print('audio2')

    elif count == 3:
        # We get here upon fetching the THIRD audio file from the list.
        # Instead of loading it, we SET `res` to the sum of `audio1+silence+audio2`
        # We don't do anything with the third file, in fact we skip it
        #
        res = (audio1 + silence + audio2)
        print('Merging')

        # Here we reset `count`, so we basically start over the same cycle:
        #  - read the NEXT two audio files, skip the third, and REPLACE `res` to the NEW sum
        #    of the current `audio1`/`audio2` files
        count = 0

    if (n + 1) == lenght:
        res.export(export_path, format='mp3')
        print('\ndone!')

Answer 1

据我所知，循环存在问题。我在原始代码下方评论（虽然只是 for 循环）以提供一些见解：

for n, mp3_file in enumerate(MP3_FILES):
    mp3_file = mp3_file.replace(chr(92), '/')
    print(n, mp3_file)

    count += 1
    if count == 1:
        # We get here upon fetching the first audio file from the list.
        # So we load it into `audio1`
        audio1 = AudioSegment.from_mp3(mp3_file)
        print('audio1')

    elif count == 2:
        # We get here upon fetching the second audio file from the list.
        # So we load it into `audio2`
        audio2 = AudioSegment.from_mp3(mp3_file)
        print('audio2')

    elif count == 3:
        # We get here upon fetching the THIRD audio file from the list.
        # Instead of loading it, we SET `res` to the sum of `audio1+silence+audio2`
        # We don't do anything with the third file, in fact we skip it
        #
        res = (audio1 + silence + audio2)
        print('Merging')

        # Here we reset `count`, so we basically start over the same cycle:
        #  - read the NEXT two audio files, skip the third, and REPLACE `res` to the NEW sum
        #    of the current `audio1`/`audio2` files
        count = 0

    if (n + 1) == lenght:
        res.export(export_path, format='mp3')
        print('\ndone!')

如果您想要 - 正如您提到的那样 - 只需将所有文件连接成一个音频，中间没有声音，您就不需要检查计数，也不需要 enumerate。我将保留 enumerate，因为它可以很好地打印以显示更多上下文。所以，这是我的看法：

from pydub import AudioSegment
from os import getcwd
import glob

cwd = (getcwd()).replace(chr(92), '/')
export_path = f'{cwd}/result.mp3'

MP3_FILES = glob.glob(pathname=f'{cwd}/*.mp3', recursive=True)

silence = AudioSegment.silent(duration=15000)
full_audio = AudioSegment.empty()    # this will accumulate the entire mp3 audios

for n, mp3_file in enumerate(MP3_FILES):
    mp3_file = mp3_file.replace(chr(92), '/')
    print(n, mp3_file)

    # Load the current mp3 into `audio_segment`
    audio_segment = AudioSegment.from_mp3(mp3_file)

    # Just accumulate the new `audio_segment` + `silence`
    full_audio += audio_segment + silence
    print('Merging ', n)

# The loop will exit once all files in the list have been used
# Then export    
full_audio.export(export_path, format='mp3')
print('\ndone!')

如何加入多个mp3文件？

How to join multiple mp3 files?

python

glob

pydub