无法在 C++ 中找到两个项目之间的差异

Question

首先让我说我对 C++ 还是非常陌生，希望让事情尽可能简单。我的数学也很差。

大多数情况下，我正在寻找是否有人可以帮助我的代码，以便它始终给出正确的结果。除了在一种情况下，我大部分时间都让它做我想做的事。

我的代码试图找出某人购买了多少包热狗威纳和多少包热狗面包。然后它会告诉用户他们可以从中制作多少热狗，以及他们将拥有多少剩余的 weiner 或面包。假设一包威纳有 12 个，一包包子有 8 个，这是我目前得出的结论：

#include <iostream>
#include <cmath>

using namespace std;

void hotdog(int a, int b){      //a = weiner packages, b = bun packages
    int weiners = 12 * a;
    int buns = 8 * b;
    int total = (weiners + buns) - (weiners - buns);
    int leftOverWeiners = total % weiners;
    int leftOverBuns = total % buns;
    int totalHotDogs = total / 2;

    cout << "You can make " << totalHotDogs << " hotdogs!" << endl;

    if (leftOverWeiners > 0){
        cout << "You have " << leftOverWeiners << " weiners left over though." << endl;
    }else if (leftOverBuns > 0){
        cout << "You have " << leftOverBuns << " buns left over though." << endl;
    }
}

int main(){
    int a;
    int b;

    cout << "Let's see how many hotdogs you can make!" << endl;
    cout << "How many weiner packages did you purchase?: ";
    cin >> a;
    cout << "How many bun packages did you purchase?: ";
    cin >> b;

    hotdog(a, b);

    return 0;
}

有了这个，如果馒头和馒头的比例相同，或者馒头比馒头多，我总能得到正确答案。

由于我设置总 and/or leftOverBuns 的方式（第 9、11 行），我永远无法得到剩余面包的正确答案。我知道如果不能修改我当前的代码，那么必须有一种更简单的方法来执行此操作，但我很困惑。

我知道我几乎留下了零符号，所以如果你想要一些请告诉我！

Answer 1

#include <iostream>

void hotdog( int weinerspackages, int bunspackages ){
    const int weinersPerPackage = 12;
    const int bunsPerPackage = 8;
    const int totalweiners = weinerspackages * weinersPerPackage;
    const int totalbuns = bunspackages * bunsPerPackage;
    int leftoverweiners = 0;
    int leftoverbuns = 0;
    int amountOfHotdogs = 0;

    if( totalweiners > totalbuns ){
        leftoverweiners = totalweiners - totalbuns;
        amountOfHotdogs = totalbuns;
        leftoverbuns = 0;
    }
    else if( totalbuns > totalweiners ){
        leftoverbuns = totalbuns - totalweiners;
        amountOfHotdogs = totalweiners;
        leftoverweiners = 0;
    }
    else{
        amountOfHotdogs = totalweiners;
        leftoverweiners = 0;
        leftoverbuns = 0;
    }

    std::cout << "You can make: " << amountOfHotdogs << " Hotdogs" << std::endl;
    std::cout << "Leftover Weiners: " << leftoverweiners << " || Leftover Buns: " << leftoverbuns << std::endl;
}

int main(){
    int PackagesW = 8;
    int PackagesB = 12;

    hotdog( PackagesW, PackagesB );

    system("pause");
    return 0;
}

注意：可以用更少的变量来做到这一点，我声明了这个数量的变量是为了更容易理解数字代表什么。

假设做一个热狗只需要每一种，你可以找出你所用的材料最少的，你能做的热狗的数量将受到该材料数量的限制，即为什么 amountOfHotdogs 取较小的值。如果两者的数量相等，那么amountOfHotdogs可以取其中一个的数量。

只有量大的食材才会有剩菜，因此leftoverweiners = totalweiners - totalbuns;当totalweiners > totalbuns反之亦然。

Answer 2

你把事情搞得太复杂了。试试这个：

if(weiners > buns)
{
  cout << "You can make " << buns << " hotdogs!" << endl;
  cout << "with " << weiners-buns << " weiners left over" << endl;
  return;
}
cout << "You can make " << weiners << " hotdogs!" << endl;
if(buns > weiners)
{
  cout << "with " << buns-weiners << " buns left over" << endl;
}

{buns, weiners} 中较小的是热狗的数量，if-then 块决定函数是否报告剩余的面包或 weiners。

无法在 C++ 中找到两个项目之间的差异

Trouble finding differential between two items in C++

c++

modulo

cmath