如何从 python 脚本创建多个 PlantUML 图？

Question

场景

大多数说明建议您可以使用 python 生成 PlantUML 图：python -m plantuml example_diagram.txt。我想创建一个 python 脚本，它在创建时生成多个 PlantUML 图，这样我就可以立即更新一整套图，而无需运行多个命令。

示例文件

以下文件用于生成 PlantUML 图：

example_flow.txt 内容：

' http://tonyballantyne.com/graphs.html#orgheadline19
' http://graphviz.org/doc/info/shapes.html

' Indicate the direction of the flowchart
left to right direction

' Give a block the variable name 'first' and define starting point as (*)
(*) --> "The first block" as first

first --> "A" as A
' Give the block a variable name s.t. you can just use its variable name in the next blocks
  --> "D" as D
first --> "B" as B
  --> D
first --> "C" as C
  --> D
  
' Define end point as (*)  
D --> (*)

Graphviz_example.txt 内容：

' http://tonyballantyne.com/graphs.html#orgheadline19
' http://graphviz.org/doc/info/shapes.html

digraph summary{
    // initialize the variable blocks
    start [label="Start with a Node"]
    next [label="Choose your shape", shape=box]
    warning [label="Don't go overboard", color=Blue, fontcolor=Red,fontsize=24,style=filled, fillcolor=green,shape=octagon]
    end [label="Draw your graph!", shape=box, style=filled, fillcolor=yellow]

    // Indicate the direction of the flowchart
    rankdir=LR; // Rank direction left to right
    
    // Create the connections
    start->next
    start->warning 
    next->end [label="Getting Better...", fontcolor=darkblue]

}

问题

如何从单个 python 脚本创建这些图表？

Answer 1

在同一目录下生成2个文件

创建一个名为 create_diagrams.py 的 python 文件，内容为：

from plantuml import PlantUML
from os.path import abspath

# create a server object to call for your computations
server = PlantUML(url='http://www.plantuml.com/plantuml/img/',
                          basic_auth={},
                          form_auth={}, http_opts={}, request_opts={})

# Send and compile your diagram files to/with the PlantUML server
server.processes_file(abspath('./example_flow.txt'))
server.processes_file(abspath('./Graphviz_example.txt'))

和运行它，例如在 anaconda 中使用 python 3.6 使用命令：python create_diagrams.py.

为目录中的所有文件生成

还可以为名为 Diagrams 的目录中的所有 .txt 文件生成图表：

from plantuml import PlantUML
import os
from os.path import abspath

server = PlantUML(url='http://www.plantuml.com/plantuml/img/',
                          basic_auth={},
                          form_auth={}, http_opts={}, request_opts={})


# create subfolder name
diagram_dir = "./Diagrams"

# loop through all .txt files in the subfolder
for file in os.listdir(diagram_dir):
  filename = os.fsdecode(file)
  if filename.endswith(".txt"):
    # Call the PlantUML server on the .txt file
    server.processes_file(abspath(f'./Diagrams/{filename}'))

注释

此实现需要有效的互联网连接，因为您要求 PlantUML 服务器为您生成图形。要在本地编译，您还可以下载 PlantUML 软件的 .jar 文件并从 python 调用它来进行计算。 the question of this post.

中给出了更详细的示例

如何从 python 脚本创建多个 PlantUML 图？

How to create multiple PlantUML diagrams from a python script?

python

diagram

flowchart

plantuml

场景

示例文件

问题

在同一目录下生成2个文件

为目录中的所有文件生成

注释