如何在包含占位符的字典中加载 yaml 文件内容？

Question

输入yaml文件

kind: Testing

metadata:

   name: test-file

   annotations:

      purpose: To test the deployed code

spec:
   containers:

     - name: client

       image: {{.registry}}/xyz:{{.client}}

       env:

         {{ if ne .proxy ""  }}

         - name: http_proxy

         value: "{{.proxy}}"

         {{ end -}}

我想加载字典中除占位符内容之外的所有 yaml 内容。我怎样才能实现它？我可以使用任何正则表达式来过滤占位符吗？

我尝试使用以下代码，它适用于没有占位符值但在上述 yaml 中给出解析错误的 yaml。

def __load_yaml(filename):
  with open(filename, 'r') as stream:
    try:
        return yaml.load(stream, Loader=yaml.FullLoader)
    except yaml.YAMLError as exception:
        raise exception
 
 def main():
   data = {}
   data.update(__load_yaml(file))
   print(data)

 if __name__ == '__main__':
   main()

我也试过这个，它正在加载yaml到字典，但也给出了FileNotFoundError。有没有办法将列表读取为流？或者有什么建议可以实现吗？:

def __load_yaml(filename):

with open(filename, 'r') as stream:
    try:
        data = []
        for text in stream:
            match = re.search(r'\{\{.*?\}\}', text)
            if not match and text != None:
                data.append(text)
        with open(str(data), 'r') as stream:
            return yaml.load(stream, Loader=yaml.FullLoader)
    except yaml.YAMLError as exception:
        raise exception

Answer 1

def __load_yaml(filename):
  with open(filename, "r") as stream:
    string = stream.read()
    # Find placeholders
    reg_one = re.findall(r':\{\{.*?\}\}', string)
    reg_two = re.findall(r'\{\{.*?\}\}', string)
    placeholders = reg_one + reg_two
    # Replace placeholders
    for placeholder in placeholders:
        string = string.replace(placeholder, "")
    try:
        return yaml.load(string, Loader=yaml.FullLoader)
    except yaml.YAMLError as exception:
        raise exception

如何在包含占位符的字典中加载 yaml 文件内容？

How can I load a yaml file content in a dictionary containing placeholders?

python

pyyaml

python-3.x