如何使用 node-soap 服务器 return 一个 XML?
How to return an XML with node-soap server?
我正在使用 Express 创建一个包含 API REST 和 SOAP 方法(我使用 https://www.npmjs.com/package/soap)的 NodeJS Web 服务。使用 API REST 我没有任何问题但是使用 SOAP 我有一个不方便,当我尝试从测试 C# 应用程序使用 SOAP 方法时我可以看到参数正常,但在响应中我在 C# 中出现下一个错误(响应不正确 XML 代码)
当我使用 node-soap 来自 NodeJS 客户端的方法时,响应工作正常。
我的部分 NodeJS 代码:
const express = require('express');
const bodyParser = require('body-parser');
const soap = require('soap');
const fs = require('fs');
const xml = fs.readFileSync('src/templates/ws_soap.wsdl', 'utf8');
const app = express();
app.use(bodyParser.urlencoded({
extended: false
}));
app.use(bodyParser.json());
const soap_service = {
integrations: {
pull: {
getSnapshotGIGA: function(args) {
return {
res: "HOLA"
};
},
}
}
};
app.listen(port, ip, function() {
soap.listen(app, '/integrations_service', soap_service, xml, function() {
console.log('SOAP web service started on ' + ip + ':' + port);
});
console.log('API REST started on ' + ip + ':' + port);
});
我的 WSDL 文件是下一个(作为响应,我有类型字符串,因为我想看看它的行为方式,但我需要 return 一个 object XML):
<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions name="integrations_service" targetNamespace="http://localhost:4205/integrations_service" xmlns="http://localhost:4205/integrations_service" xmlns:http="http://schemas.xmlsoap.org/wsdl/http/" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<wsdl:message name="getSnapshotGIGARequest">
<wsdl:part name="User" type="xs:string"/>
<wsdl:part name="Password" type="xs:string"/>
</wsdl:message>
<wsdl:message name="getSnapshotGIGAResponse">
<wsdl:part name="res" type="xs:string"/>
</wsdl:message>
<wsdl:portType name="pull_integrations">
<wsdl:operation name="getSnapshotGIGA">
<wsdl:input message="getSnapshotGIGARequest"/>
<wsdl:output message="getSnapshotGIGAResponse"/>
</wsdl:operation>
</wsdl:portType>
<wsdl:binding name="pull_integrations_binding" type="pull_integrations">
<soap:binding style="rpc" transport="http://schemas.xmlsoap.org/soap/http"/>
<wsdl:operation name="getSnapshotGIGA">
<soap:operation soapAction="getSnapshotGIGA"/>
<wsdl:input>
<soap:body encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" use="literal"/>
</wsdl:input>
<wsdl:output>
<soap:body encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" use="literal"/>
</wsdl:output>
</wsdl:operation>
</wsdl:binding>
<wsdl:service name="integrations">
<wsdl:port binding="pull_integrations_binding" name="pull">
<soap:address location="http://localhost:4205/integrations_service"/>
</wsdl:port>
</wsdl:service>
</wsdl:definitions>
在 C# 中,我有一个控制台应用程序,并且我已将 SOAP 服务注册为 Web 引用。
我使用 SOAP 方法的方式是(当我使用 C# 创建 SOAP 服务时,我也通过这种方式测试方法,因为这是客户端的工作方式):
Console.WriteLine("Consume NodeJS SOAP service");
Thread.Sleep(500);
integrations_service.integrations integrations = new integrations_service.integrations();
integrations.Url = "http://localhost:4205/integrations_service?wsdl";
var some_response = integrations.getSnapshotGIGA("myuser", "123456");
Console.WriteLine("Press enter to out...");
我想在 XmlNode 中获得响应,就像在这个例子中一样:
Console.WriteLine("Consume C# SOAP service");
Thread.Sleep(500);
serviceSOAP sSOAP = new serviceSOAP ();
sSOAP.Url = "http://my.domain.com.mx/";
XmlNode xmlNode = sSOAP .anyMethodSoap("yomero", "123456");
Console.WriteLine(XElement.Parse(xmlNode.OuterXml).ToString());
Thread.Sleep(500);
如果您知道我如何 return 来自 NodeJS 的 XML 并在 C# 中正确获取它或任何想法,我将不胜感激。雷格德。
回答我的问题,问题出在 WSDL 配置上。通过此配置,我使它可以与 C# Web 参考一起使用。主要问题,样式,我将其从“rpc”更改为“document”并正确配置响应元素。
<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions
name="devices_service"
targetNamespace="http://localhost:4205/devices_service"
xmlns:http="http://schemas.xmlsoap.org/wsdl/http/"
xmlns:s="http://schemas.xmlsoap.org/wsdl/soap/"
xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns="http://localhost:4205/devices_service">
<wsdl:types>
<xs:schema targetNamespace="http://localhost:4205/devices_service" xmlns="http://localhost:4205/devices_service" attributeFormDefault="qualified" elementFormDefault="qualified">
<xs:element name="GetDevicesRequest">
<xs:complexType>
<xs:sequence>
<xs:element minOccurs="0" maxOccurs="1" name="User" type="xs:string"/>
<xs:element minOccurs="0" maxOccurs="1" name="Password" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="GetDevicesResponse">
<xs:complexType>
<xs:sequence>
<xs:any/>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>
</wsdl:types>
<wsdl:message name="GetDevicesSoapIn">
<wsdl:part name="parameters" element="GetDevicesRequest"/>
</wsdl:message>
<wsdl:message name="GetDevicesSoapOut">
<wsdl:part name="parameters" element="GetDevicesResponse"/>
</wsdl:message>
<wsdl:portType name="user_devices">
<wsdl:operation name="GetDevices">
<wsdl:input message="GetDevicesSoapIn"/>
<wsdl:output message="GetDevicesSoapOut"/>
</wsdl:operation>
</wsdl:portType>
<wsdl:binding name="user_devices_binding" type="user_devices">
<s:binding transport="http://schemas.xmlsoap.org/soap/http" style="rpc"/>
<wsdl:operation name="GetDevices">
<s:operation soapAction="http://localhost:4205/devices_services/GetDevices"/>
<wsdl:input>
<s:body use="literal" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"/>
</wsdl:input>
<wsdl:output>
<s:body use="literal" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"/>
</wsdl:output>
</wsdl:operation>
</wsdl:binding>
<wsdl:service name="devices">
<wsdl:port binding="user_devices_binding" name="user">
<s:address location="http://localhost:4205/devices_service"/>
</wsdl:port>
</wsdl:service>
</wsdl:definitions>**
您可能想要使用以下之一:
节点肥皂
strong-soap(重写 node-soap)
easysoap
我正在使用 Express 创建一个包含 API REST 和 SOAP 方法(我使用 https://www.npmjs.com/package/soap)的 NodeJS Web 服务。使用 API REST 我没有任何问题但是使用 SOAP 我有一个不方便,当我尝试从测试 C# 应用程序使用 SOAP 方法时我可以看到参数正常,但在响应中我在 C# 中出现下一个错误(响应不正确 XML 代码)
当我使用 node-soap 来自 NodeJS 客户端的方法时,响应工作正常。
我的部分 NodeJS 代码:
const express = require('express');
const bodyParser = require('body-parser');
const soap = require('soap');
const fs = require('fs');
const xml = fs.readFileSync('src/templates/ws_soap.wsdl', 'utf8');
const app = express();
app.use(bodyParser.urlencoded({
extended: false
}));
app.use(bodyParser.json());
const soap_service = {
integrations: {
pull: {
getSnapshotGIGA: function(args) {
return {
res: "HOLA"
};
},
}
}
};
app.listen(port, ip, function() {
soap.listen(app, '/integrations_service', soap_service, xml, function() {
console.log('SOAP web service started on ' + ip + ':' + port);
});
console.log('API REST started on ' + ip + ':' + port);
});
我的 WSDL 文件是下一个(作为响应,我有类型字符串,因为我想看看它的行为方式,但我需要 return 一个 object XML):
<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions name="integrations_service" targetNamespace="http://localhost:4205/integrations_service" xmlns="http://localhost:4205/integrations_service" xmlns:http="http://schemas.xmlsoap.org/wsdl/http/" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<wsdl:message name="getSnapshotGIGARequest">
<wsdl:part name="User" type="xs:string"/>
<wsdl:part name="Password" type="xs:string"/>
</wsdl:message>
<wsdl:message name="getSnapshotGIGAResponse">
<wsdl:part name="res" type="xs:string"/>
</wsdl:message>
<wsdl:portType name="pull_integrations">
<wsdl:operation name="getSnapshotGIGA">
<wsdl:input message="getSnapshotGIGARequest"/>
<wsdl:output message="getSnapshotGIGAResponse"/>
</wsdl:operation>
</wsdl:portType>
<wsdl:binding name="pull_integrations_binding" type="pull_integrations">
<soap:binding style="rpc" transport="http://schemas.xmlsoap.org/soap/http"/>
<wsdl:operation name="getSnapshotGIGA">
<soap:operation soapAction="getSnapshotGIGA"/>
<wsdl:input>
<soap:body encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" use="literal"/>
</wsdl:input>
<wsdl:output>
<soap:body encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" use="literal"/>
</wsdl:output>
</wsdl:operation>
</wsdl:binding>
<wsdl:service name="integrations">
<wsdl:port binding="pull_integrations_binding" name="pull">
<soap:address location="http://localhost:4205/integrations_service"/>
</wsdl:port>
</wsdl:service>
</wsdl:definitions>
在 C# 中,我有一个控制台应用程序,并且我已将 SOAP 服务注册为 Web 引用。
我使用 SOAP 方法的方式是(当我使用 C# 创建 SOAP 服务时,我也通过这种方式测试方法,因为这是客户端的工作方式):
Console.WriteLine("Consume NodeJS SOAP service");
Thread.Sleep(500);
integrations_service.integrations integrations = new integrations_service.integrations();
integrations.Url = "http://localhost:4205/integrations_service?wsdl";
var some_response = integrations.getSnapshotGIGA("myuser", "123456");
Console.WriteLine("Press enter to out...");
我想在 XmlNode 中获得响应,就像在这个例子中一样:
Console.WriteLine("Consume C# SOAP service");
Thread.Sleep(500);
serviceSOAP sSOAP = new serviceSOAP ();
sSOAP.Url = "http://my.domain.com.mx/";
XmlNode xmlNode = sSOAP .anyMethodSoap("yomero", "123456");
Console.WriteLine(XElement.Parse(xmlNode.OuterXml).ToString());
Thread.Sleep(500);
如果您知道我如何 return 来自 NodeJS 的 XML 并在 C# 中正确获取它或任何想法,我将不胜感激。雷格德。
回答我的问题,问题出在 WSDL 配置上。通过此配置,我使它可以与 C# Web 参考一起使用。主要问题,样式,我将其从“rpc”更改为“document”并正确配置响应元素。
<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions
name="devices_service"
targetNamespace="http://localhost:4205/devices_service"
xmlns:http="http://schemas.xmlsoap.org/wsdl/http/"
xmlns:s="http://schemas.xmlsoap.org/wsdl/soap/"
xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns="http://localhost:4205/devices_service">
<wsdl:types>
<xs:schema targetNamespace="http://localhost:4205/devices_service" xmlns="http://localhost:4205/devices_service" attributeFormDefault="qualified" elementFormDefault="qualified">
<xs:element name="GetDevicesRequest">
<xs:complexType>
<xs:sequence>
<xs:element minOccurs="0" maxOccurs="1" name="User" type="xs:string"/>
<xs:element minOccurs="0" maxOccurs="1" name="Password" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="GetDevicesResponse">
<xs:complexType>
<xs:sequence>
<xs:any/>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>
</wsdl:types>
<wsdl:message name="GetDevicesSoapIn">
<wsdl:part name="parameters" element="GetDevicesRequest"/>
</wsdl:message>
<wsdl:message name="GetDevicesSoapOut">
<wsdl:part name="parameters" element="GetDevicesResponse"/>
</wsdl:message>
<wsdl:portType name="user_devices">
<wsdl:operation name="GetDevices">
<wsdl:input message="GetDevicesSoapIn"/>
<wsdl:output message="GetDevicesSoapOut"/>
</wsdl:operation>
</wsdl:portType>
<wsdl:binding name="user_devices_binding" type="user_devices">
<s:binding transport="http://schemas.xmlsoap.org/soap/http" style="rpc"/>
<wsdl:operation name="GetDevices">
<s:operation soapAction="http://localhost:4205/devices_services/GetDevices"/>
<wsdl:input>
<s:body use="literal" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"/>
</wsdl:input>
<wsdl:output>
<s:body use="literal" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"/>
</wsdl:output>
</wsdl:operation>
</wsdl:binding>
<wsdl:service name="devices">
<wsdl:port binding="user_devices_binding" name="user">
<s:address location="http://localhost:4205/devices_service"/>
</wsdl:port>
</wsdl:service>
</wsdl:definitions>**
您可能想要使用以下之一:
节点肥皂 strong-soap(重写 node-soap) easysoap