在菜单功能中调用和显示文本文件

Question

我是 C++ 的新手，我的任务非常艰巨。我必须创建一个菜单（我在其中挣扎得很厉害），不仅如此，我还应该阅读和显示一个文本文件。到目前为止，我使用的唯一方法只显示文本文件的第一行。你能帮我吗？提前致谢。

添加到第一个案例中的中断功能也使循环成为无限的文本墙！不知道怎么办..

    // Assignment 1.cpp : Tally Ho Generator

#include <iostream>
#include <fstream>
#include <string>
using namespace std;

int runMenu;

int main()
{
    int menuInput;
    bool menu = true;
    ifstream inFile;
    string ABOUT;

    // Menu Interface
    cout << "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\n";
    cout << "   The Tally Ho Probability Generator (MCD4720_Assignment 1)\n";
    cout << "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\n";
    cout << " [1] End Testing the Program\n";
    cout << " [2] Display About Information\n";
    cout << " [3] Read and store data from files\n";
    cout << " [4] Generate a Dice Tally Table\n";
    cout << " [5] Save Tally Statistics to a file\n";
    cout << " [6] Load Tally Statistics from a file\n";
    cout << "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\n";
    cout << "Which Option would you like (1-6)\n";
    cin >> runMenu;


    // Menu Input Function
    while (menu != false) {
        switch (runMenu)
        {
        case 1:
        {

            inFile.open("C:\Users\William\Documents\MCD Assignment 4720 1\TallyAbout.txt");
            while (getline(inFile, ABOUT)) {
                cout << ABOUT << endl;
                inFile.close();

            }
            break;
        }
        

        case 2:
        {}
        case 3:
        {}
        case 4:
        {}
        case 5:
        {}
        case 6:
        {}

        default: {
            cout << " Input unrecognized, please choose again \n";
            cin >> runMenu;
            break;
        }
        }
        }


        cin.ignore();
        cin.get();

        return 1;
    }

Answer 1

试试这个：

case 1:
{
    inFile.open("C:\Users\William\Documents\MCD Assignment 4720 1\TallyAbout.txt");
    while (getline(inFile, ABOUT)) {
        cout << ABOUT << endl;
    }

    inFile.close();
    break;
}

您正在阅读第一行后关闭文件现在的区别是您在阅读所有行后关闭文件

Answer 2

So far, the only method I used only displays the first lines of the text file

那是因为你读完第一行就关闭了文件:

        while (getline(inFile, ABOUT)) {
            cout << ABOUT << endl;
            inFile.close();                // <------ here !!

        }

您不需要明确关闭文件。该文件在 inFile.

的析构函数中关闭

The break function when added to the first case also makes the loop an infinite wall of texts! I dont know what to do..

那是因为break跳出了开关。不会处理其他情况。特别是，您要求用户输入的 default 案例将不会执行。实际上你永远不会修改 menu 的值并且 while(menu != false) 是一个无限循环。将任何情况下必须完成的部分移出开关：

while (menu != false) {
    switch (runMenu)
    {
        case 1:
        {

            inFile.open("C:\Users\William\Documents\MCD Assignment 4720 1\TallyAbout.txt");
            while (getline(inFile, ABOUT)) {
                cout << ABOUT << endl;
                inFile.close();

            }
            break;
        }
        
        //...
        default: {
            cout << " Input unrecognized, please choose again \n";      
            break;
        }
    }
  
    cin >> runMenu;
    // put logic here, for example:
    menu = (runMenu == 1);
}

您应该相应地修改输出。目前它说“输入无法识别，请重新选择”，但如果我理解正确，用户必须在每次迭代中选择继续或不继续。 menu 和 runMenu 使用一个变量而不是两个变量会更不容易出错。

在菜单功能中调用和显示文本文件

Summoning and Displaying a text file, inside a menu function

c++

menu

function

text-files

switch-statement