terraform 12 嵌套映射

Question

只是想请您帮忙，我的 main.tf 文件如何取 "labrador" 的值] 来自 variables.tfvars

的嵌套变量

variables.tfvars

PETS = {
  dog = {
    indoor                          = "poodle"
    outdoor                         = "labrador"
    others                          = "bulldog"

  }
  cat = {
    indoor                          = "siamese"
    outdoor                         = "persian"
    others                          = "bengal"

  }
}

variables.tf

variable PETS { type = map }

main.tf

module "lambda-module" {
  source                        = "../../module/lambda-module"
  PETS                          = var.PETS[var.TYPE[var.BREED]]
}

我想执行它并获取正确的值并使用此命令分配给 lambda 模块：

terraform plan -var-file=variables.tf -var "TYPE=dog" -var "BREED=outdoor"

但是我遇到了这个问题：

Error: Invalid index

  on main.tf line 3, in module "lambda-module":

3:   PETS          = var.PETS[var.TYPE[var.BREED]]
    |----------------
    | var.TYPE is "dog"
    | var.BREED is "outdoor"

Answer 1

您的问题在：
var.PETS[var.TYPE[var.BREED]]
应该是：
var.PETS[var.TYPE][var.BREED]

这是一个例子：

variable PETS {
  type = map
  default = {
    "dog" = {
      indoor  = "poodle"
      outdoor = "labrador"
      others  = "bulldog"
    },
    "cat" = {
      indoor  = "siamese"
      outdoor = "persian"
      others  = "bengal"
    }
  }
}

variable TYPE {
  type = string
}

variable BREED {
  type = string
}


output "TYPE_BREED" {
  value = var.PETS[var.TYPE][var.BREED]
}

terraform apply -var "TYPE=dog" -var "BREED=outdoor"

Apply complete! Resources: 0 added, 0 changed, 0 destroyed.

Outputs:

TYPE_BREED = labrador

terraform apply -var "TYPE=cat" -var "BREED=indoor"

Apply complete! Resources: 0 added, 0 changed, 0 destroyed.

Outputs:

TYPE_BREED = siamese

terraform 12 嵌套映射

terraform 12 nested mapping

terraform

terraform0.12+