尝试在抽象的具体实现中覆盖泛型函数时出现类型错误 class

Question

可以使用以下代码在控制台中重现该错误。

case class SomeClass(name: String)

abstract class Factory() {
  protected def create[U](name: String) : U
}

class SomeFactory extends Factory() {
  override def create[SomeClass](name: String) = SomeClass(name)
}

<console>:11: error: type mismatch;
found : SomeClass(in object $iw) required: SomeClass(in method create) override def create[SomeClass](name: String) = SomeClass(name)

Answer 1

看来这就是您要实现的目标：

case class SomeClass(name: String)

abstract class Factory[U]() {
  protected def create(name: String) : U
}

class SomeFactory extends Factory[SomeClass] {
  def create(name: String) = SomeClass(name)
}

（我假设你的意思是 SomeFactory 扩展 Factory）

尝试在抽象的具体实现中覆盖泛型函数时出现类型错误 class

Type error when when trying to override a generic function in a concrete implementation of an abstract class

generics

scala

abstract