如何从 mysql 连接接收 1 行而不是 4 行

Question

SELECT
    pe.entity_id,
    pev.attribute_id,
    pev.entity_id,
    if(pev.attribute_id='134', pev.value, null) as garantie,
    if(pev.attribute_id='97', pev.value, null) as url,
    if(pev.attribute_id='71', pev.value, null) as nume,
    if(pev.attribute_id='85', pev.value, null) as poza
    FROM
    mg_catalog_product_entity pe,
    mg_catalog_product_entity_varchar pev
    WHERE
    pev.entity_id=pe.entity_id and
    (pev.attribute_id='134' or pev.attribute_id='97'  or pev.attribute_id='71'  or pev.attribute_id='85')

我有这个 mysql 加入那个 returns 4 行，像这样：

value1 null null null 
null value2 null null 
null null value3 null 
null null null value4

我必须做什么才能像这样只收到一行？

value1 value2 value3 value4

Answer 1

SELECT 
    pe.entity_id,
    max(if(pev.attribute_id='134', pev.value, null)) as garantie,
    max(if(pev.attribute_id='97', pev.value, null)) as url,
    max(if(pev.attribute_id='71', pev.value, null)) as nume,
    max(if(pev.attribute_id='85', pev.value, null)) as poza
FROM
    mg_catalog_product_entity pe
JOIN
    mg_catalog_product_entity_varchar pev
ON 
    pev.entity_id = pe.entity_id
WHERE 
    pev.attribute_id in (134,97,71,85)
GROUP BY 
    pe.entity_id

如何从 mysql 连接接收 1 行而不是 4 行

How to receive 1 row from a mysql join instead of 4

mysql

sql

join