在 Lua 中按下按键时如何执行功能？

Question

我只想在按下“+”键时执行 findSum() 函数。所以当我按“+”键时，然后必须调用函数 findSum()。这是我目前的程序：

numberOfInput = 0                                               
sum = 0                                                         


io.write('\t', "Welcome to My Calculator", '\n')
repeat
io.write("for addition, press '+' :", '\n')
findSumSection = io.read()
until
(string.match(findSumSection, '+'))

function findSum()                              
io.write("Enter the amount of feed(s):",'\n')                   
numberOfInput = io.read()
x = numberOfInput                                               
for i = 1, x, 1 do                                                  
io.write('\n',"enter the number: ")
inputs = io.read()                                              
sum = sum + inputs                                              
end
return sum
end

io.write('\n',"The Sum of your feeds is:", '\n' , findSum(), '\n')  

io.write("Do you want to continue? [Y/N]")  
inputYesorNo = io.read()  


if (string.match(inputYesorNo, 'yes')) then
    print("Starting the program again")
    
else if(string.match(inputYesorNo, 'no')) then
os.exit()                                               
else
print("The program can not understand the procedure")       
end
end

Answer 1

我运行你的代码并收到了这个输出。你在期待什么？

        Welcome to My Calculator
for addition, press '+' :
+
Enter the amount of feed(s):
3

enter the number: 1

enter the number: 2

enter the number: 3

The Sum of your feeds is:
6
Do you want to continue? [Y/N]no

请注意，我修复了运行代码前的缩进。

Answer 2

Mike67 感谢您测试程序。我想我解决了这个问题。我想做的是，当我按下“+”键时，我想转到函数 findSum() 以使其执行。我在另一个程序中解决了这个问题。看看

function printMyName()
name = io.read()
return name
end

function findYourAge()
io.write("enter the current year:")
currentYear = io.read()
io.write('\n',"enter the year you were born:")
bornYear = io.read()
age = currentYear - bornYear
updatedAge = math.abs(age)
return updatedAge
end

function ageLimitToVote()
ageLimit = 18
newAgeForVote = 0
if(updatedAge < ageLimit) then
repeat 
updatedAge = updatedAge + 1
until 
updatedAge == ageLimit
newAgeForVote = updatedAge
return newAgeForVote
end
end

io.write("What is your name ", '\n')
io.write("your name is ", printMyName(), '\n')

io.write("Do you want to find your age?", '\n')
answer = io.read()
if(string.match(answer, 'yes')) then
findYourAge()
elseif(string.match(answer, 'no')) then 
os.exit()
end

if(updatedAge > 16) then
io.write(name, " you are matured enough to vote", '\n')
else
io.write(name, " you are ", updatedAge, " years old. and you have to wait until                you are ", ageLimitToVote(), '\n')
end

*这是我认为目前为止最好的解决方案。

if(string.match(answer, 'yes')) then
findYourAge()

在 Lua 中按下按键时如何执行功能？

How can I execute a function when key is pressed in Lua?

function

keypress

execution