Preg_Mach_All如何消除结尾字符

Question

我喜欢preg_mach_all命令，但现在我遇到了这种情况：

$lotes_fil='/((?:https?|http?):\/\/(?:\S*?\.\S*?)(?:[\s)\[\]{};"\'<]|\.\s|$))/';

preg_match_all($lotes_fil,$rs,$link_pre, PREG_SET_ORDER);

输出是这样的：

[0] => Array
    (
        [0] => https://s3.amazonaws.com/mesena.com/vodcategories/58e1a299dca3c3a22fbd8319/iconPng-1576021669572.png"
        [1] => https://s3.amazonaws.com/mesena.com/vodcategories/58e1a299dca3c3a22fbd8319/iconPng-1576021669572.png"
    )

[1] => Array
    (
        [0] => https://images.mesena.com/assets/images/default/vodcategory.id-imageFeatured.jpg"
        [1] => https://images.mesena.com/assets/images/default/vodcategory.id-imageFeatured.jpg"
    )

[2] => Array
    (
        [0] => https://s3.amazonaws.com/silo.mesena.com/origin/5638f208fbdc021398ae8681/production/202006/19/5638f208fbdc021398ae8681_212-21719"
        [1] => https://s3.amazonaws.com/silo.mesena.com/origin/5638f208fbdc021398ae8681/production/202006/19/5638f208fbdc021398ae8681_212-21719"
    )

我需要删除最后一个 " 但我想使用这个正则表达式因为对我有用 well.In 原始数据有 " 作为每个 URL

的结尾

谢谢你的帮助。

Answer 1

我会使用：

~https?://[^\s"]+~

解释：

~       # regex delimiter, it allows to use / without escaping
https?    # http OR https
://       # literally
[^\s"]+   # 1 or more any character that is not a space or double quote

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