在 JS 警报中显示 PHP 变量
Show PHP variable in JS alert
我正在尝试提醒消息,但它不适用于我的字符串。
echo "<script>alert('$lang['ALERT']');
window.location.href ='index.php';
</script>";
不工作...帮助
你在混淆引号。保持简单,
echo "<script>alert('".$lang['ALERT']."');
window.location.href ='index.php';
</script>";
试一试。
<script>
var alertMsg = "<?php echo $lang['ALERT'] ?>";
alert(alertMsg);
window.location.href ='index.php';
</script>;
您没有正确引用您的变量
<?php
$lang['ALERT'] = 'mystring';
echo "<script>alert('".$lang['ALERT']."');window.location.href ='index.php';</script>";
?>
试试这个
<script>
alert(<?=$lang['ALERT']; ?>);
window.location.href ='index.php';
</script>
引用是问题
<?php $alert=$lang['ALERT'];?>
<script>
alert('<?php echo $alert?>');
window.location.href ='index.php';
</script>;
我正在尝试提醒消息,但它不适用于我的字符串。
echo "<script>alert('$lang['ALERT']');
window.location.href ='index.php';
</script>";
不工作...帮助
你在混淆引号。保持简单,
echo "<script>alert('".$lang['ALERT']."');
window.location.href ='index.php';
</script>";
试一试。
<script>
var alertMsg = "<?php echo $lang['ALERT'] ?>";
alert(alertMsg);
window.location.href ='index.php';
</script>;
您没有正确引用您的变量
<?php
$lang['ALERT'] = 'mystring';
echo "<script>alert('".$lang['ALERT']."');window.location.href ='index.php';</script>";
?>
试试这个
<script>
alert(<?=$lang['ALERT']; ?>);
window.location.href ='index.php';
</script>
引用是问题
<?php $alert=$lang['ALERT'];?>
<script>
alert('<?php echo $alert?>');
window.location.href ='index.php';
</script>;