如何 运行 javascript 中的 setInterval 中的异步函数

Question

如何在 setInterval 中 运行 异步函数，如下例所示？

 setInterval(async () => {  
            
  }, millisPerHour);

Answer 1

尝试使用此代码
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function

function resolveAfter2Seconds() {
      return new Promise(resolve => {
        setTimeout(() => {
          resolve('resolved');
        }, 2000);
      });
    }
    
    async function asyncCall() {
      console.log('calling');
      const result = await resolveAfter2Seconds();
      console.log(result);
      // expected output: "resolved"
    }
    
    asyncCall();`