如果在使用 SafariViewController 打开 url 时不成功，则处理完成

Question

如果 SafariViewController 无法像 UIApplication.shared.open 那样打开 url，是否有办法处理？这是我的功能：

if ["http", "https"].contains(url.scheme?.lowercased() ?? "") {
    // Can open with SFSafariViewController
    let safariViewController = SFSafariViewController(url: url)
    self.present(safariViewController, animated: true) {
        // no bool given?
    }
} else {
    // Scheme is not supported or no scheme is given, use openURL
    guard let url = URL(string: urlString) else {
        self.showInvalidUrlAlert()
        return
    }
    UIApplication.shared.open(url, completionHandler: { success in
        if !success {
            print("failed")
            self.showInvalidUrlAlert()
        }
    })
}

Answer 1

我认为 SFSafariViewController 没有为您的应用程序提供多少 interaction/feedback。

根据 Apple 文档：

The user's activity and interaction with SFSafariViewController are not visible to your app, which cannot access AutoFill data, browsing history, or website data.

Choosing the Best Web Viewing Class

If your app lets users view websites from anywhere on the Internet, use the SFSafariViewController class. If your app customizes, interacts with, or controls the display of web content, use the WKWebView class.

正如 Apple 所建议的，您可能想看看 WKWebView class。

Answer 2

使您的演示者视图控制器符合 SFSafariViewControllerDelegate。

class ViewController: SFSafariViewControllerDelegate

并设置 ViewController 为 SafariViewController

的代表

safariViewController.delegate = self

然后处理加载状态是否成功使用 didCompleteInitialLoad代表。

func safariViewController(_ controller: SFSafariViewController, didCompleteInitialLoad didLoadSuccessfully: Bool) {
    // Handle loadStatus. 
    print(didLoadSuccessfully)

    // if load unsuccessful, dismiss SFSafariViewController and try to open using openURL
    if !didLoadSuccessfully {
        controller.dismiss(animated: true) {
            // UIApplication.shared.open(..               
        }
    }
}

如果在使用 SafariViewController 打开 url 时不成功，则处理完成

Handle completion if no success when opening url with SafariViewController

ios

completionhandler

swift

sfsafariviewcontroller