将特定数据复制到其他sheet（带脚本）

Question

https://docs.google.com/spreadsheets/d/1mpALs4rdNj-TFFgCQ0CEBP453v-FfQJR_bBxOzQakWU/edit#gid=1256640730 （任何拥有 link 的人都可以查看此传播sheet）

我有一个“主列表”sheet 从 Google 表单收集数据，我需要脚本根据它们的“位置”将数据复制到相关的 sheet。 .othersheet的名字取自“Location”

Example 1  

Sheet 1: Contain all the data (Master List)
Name......Address...............................Location
Rose.......21,Radje Road,88888.........Kedah
Rose.......21,Radje Road,88888.........Kedah
Rose.......21,Radje Road,88888.........Penang
Stone......5,Jae Road,22222...............Penang  

Sheet 2: Copy data from Sheet 1 (Location-Kedah Only)
Name......Address...............................Location
Rose.......21,Radje Road,88888.........Kedah
Rose.......21,Radje Road,88888.........Kedah

Sheet 3: Copy data from Sheet 1 (Location-Penang Only)
Name......Address...............................Location
Rose.......21,Radje Road,88888.........Penang
Stone......5,Jae Road,22222.........Penang```

Example 2

Sheet 1: Contain all the data (Master List)
Name.....Gender
Bryan.....Male
Mei.....Female
Lily.....Female
xx.....Female
xx.....Male  

Sheet 2: Copy data from Sheet 1 (Gender-Female Only)
Name.....Gender
xx.....Female
Lily.....Female
Mei.....Female

Sheet 3: Copy data from Sheet 1 (Gender-Male Only)
Name.....Gender
Bryan.....Male

function copyDataUniqueToColG() {
  const ss=SpreadsheetApp.getActive();
  const sh=ss.getSheetByName('Master List');
  const shsr=2;//data start row on master list
  const shhr=1;//master list header row
  const hA=sh.getRange(shhr,1,1,sh.getLastColumn()).getValues().map(function(r){return[r[1],r[2],r[3],r[4],r[5],r[6]]})[0];
  const vs=sh.getRange(shsr,1,sh.getLastRow()-shsr+1,sh.getLastColumn()).getValues();
  const base='Sheet';
  let shts=ss.getSheets();
  //shts.forEach(function(s,i){if(s.getName()!='Master List'){ss.deleteSheet(s);}});//delete all other sheets
  const gvs=sh.getRange(shsr,7,sh.getLastRow()-shsr+1,1).getValues().map(function(r){return r[0]});
  const s=new Set(gvs);
  const g=[...s];//g has unique values now
  g.forEach(function(v,i){
    let sA=[];
    ss.getSheets().forEach(function(obj){sA.push(obj.getName())});
    if(sA.indexOf(v)==-1){ss.insertSheet(v);}
    let aA=[]
    aA.push(hA);//start with header row
    vs.forEach(function(r,j){
      //compare to column G value
      if(r[6]==v) {
        aA.push([r[1],r[2],r[3],r[4],r[5],r[6]]);//add rows that match
      }
    });
    let dsh=ss.getSheetByName(v);
    dsh.getRange(1,1,aA.length,aA[0].length).setValues(aA);
    SpreadsheetApp.flush();//not really necessary but fun to watch the progress
  });
}

Answer 1

在 Melaka sheet 中将其粘贴到 A2 中：

=FILTER('Master List'!A:M, 'Master List'!G:G="Melaka")

其他等等...

或者你可以在 A1 中使用这个：

=QUERY('Master List'!A:M, "where G = 'Melaka'", 1)

或者如果你想使用Apps Script，可以使用方法Range.setFormula()：

Range.setFormula("=QUERY('Master List'!A:M, 'where G = \"Melaka\"', 1)")

Answer 2

请记住 Stack Overflow 不是代码编写服务。社区中的人回答编程和代码相关的问题，但不在那里为其他人编写代码。

有了答案和评论中的信息，你要多多尝试，不明白的继续提问。如果代码是为您编写的，您不太可能会学习。话虽如此，由于您是新用户，这里有一个示例代码可以解决您的问题：

function distributeMasterToSheets(){
  // Get all sheets except master list
  var allSheets = SpreadsheetApp.getActiveSpreadsheet().getSheets();
  var destinationSheets = allSheets.slice(1);
  // And set the sheet name dependent formula in range A1 
  destinationSheets.forEach(
    function(sheet){
      sheet.getRange("A1").setFormula("=QUERY('Master List'!A:M,\"select * where G = '"+sheet.getName()+"'\",1)")
    }
  )  
}

下面的文档解释了所使用的方法，我建议您通过一些快速入门来掌握它。

将特定数据复制到其他sheet（带脚本）

Copy specific data to other sheet (with script)

scripting

copy-paste

filter

google-sheets

google-apps-script

参考文献：