如何从数据透视 table 中为 laravel 中的用户获取角色名称？

Question

Admin.php [中间人]

public function handle($request, Closure $next)
{
   if (Auth::check() && Auth::user()->role->name == 'admin') {
      return $next($request);
   }
   return Redirect::route('home');
}

I want to check if the column name of roles table is equal to admin.

I have tried with Auth::user()->role->name == 'admin').

我收到错误

Property [name] does not exist on this collection instance.

参考模型

User.php [型号]

public function role()
{
   return $this->belongsToMany(Role::class, 'role_user', 'user_id', 'role_id')->withTimestamps();
}

参考table

users table

         Schema::create('users', function (Blueprint $table) {
            $table->id();
            $table->string('name');
            $table->string('email')->unique();
            $table->string('photo')->nullable();
            $table->timestamp('email_verified_at')->nullable();
            $table->string('password');
            $table->longText('cartitems')->nullable();
            $table->longText('wishlist')->nullable();
            $table->unsignedBigInteger('discount')->default(0);
            $table->rememberToken();
            $table->timestamps();
        });

This is users table. Notice there is no role directly here.

roles table

       Schema::create('roles', function (Blueprint $table) {
            $table->id();
            $table->string('name');
            $table->string('display_name');
            $table->timestamps();
        });

This is roles table. And every user have a role such as Superadmin, admin, seller orcustomer

role_user table

        Schema::create('role_user', function (Blueprint $table) {
            $table->id();
            $table->unsignedBigInteger('user_id');
            $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');

            $table->unsignedBigInteger('role_id');
            $table->foreign('role_id')->references('id')->on('roles')->onDelete('cascade');

            $table->timestamps();
        });

In this pivot table make a relationship between users and roles table.

Answer 1

这是因为根据您的架构设计，用户可以拥有多个角色。

用户 <=> 角色：多对多关系

所以Auth::user()->role给出了角色模型实例的集合。而您正在尝试访问无法完成的集合中的名称属性。

将 if 条件更改为此

if (Auth::check() && Auth::user->role()->where('name', 'admin')->exists()) {

我还建议您将用户模型中的关系名称从 role 更改为 roles。因为 roles 更能提供有关用户和角色份额关系类型的信息。

public function roles(){
  return $this->belongsToMany(App\Role::class, 'role_user' 'user_id', 'role_id');
}

Answer 2

那是因为您正在尝试访问 collection 上的值，而您的 laravel 关系是 BelongsToMany but rather HasOne/BelongsTo。您应该选择所有名称，然后检查它是否存在 in_array

$roles = Auth::check() ? Auth::user()->role->pluck('name')->toArray() : [];

if (in_array('admin', $roles)) {
  return $next($request);
}

我建议将 role 关系更改为 roles，因为在这种情况下，一个用户可以拥有多个角色。

Answer 3

你可以使用whereHas

 if (Auth::check() && User::where('id',Auth::user()->id)->whereHas('role',function ($query){
           $query->where('roles.name','=','admin');
       })->first()!=null ) {
      return $next($request);
   }

Answer 4

使用whereHas

$role = User::where('id',Auth::user()->id)->whereHas('role',function ($query){
           $query->where('name','=','admin');
       })->first();

if (Auth::check() && isset($role) && !empty($role) ) {
      return $next($request);
}

如何从数据透视 table 中为 laravel 中的用户获取角色名称？

How to get the name of role from pivot table for a users in laravel?

database

query-builder

laravel