$ 带 upsert 的位置更新运算符

Question

假设我有一系列商店：

[
  {
    "_id": 0,
    "items": [
      {"_id": 3, "price": 10}
    ]
  },
  {
    "_id": 1,
    "items": []
  },
  {
    "_id": 2
  }
]

我想将商店中商品 3 的 price 更新为 30，如果该商店中没有商品，则在商店中插入一个新商品 and/or 如有必要，插入一个新商店：

shop 0: 简单更新商品
商店 1：将 {"_id": 3, "price": 30} 附加到商店 1 的 items
店铺 2：将店铺 2 的 items 设置为 [{"_id": 3, "price": 30}]
店铺3：插入文件{"_id": 3, "items": [{"_id": 3, "price": 30}]}

换句话说，我想：

collection.updateOne({_id: <shopId>, 'items._id': 3}, {$set: {'items.$.price': 30}}) 如果商品存在（商店 0）
collection.updateOne({_id: <shopId>}, {$push: {items: {_id: 3, price: 30}}}, {upsert: true}) 如果没有（商店 1 到 3）

这有点像 $ 和 upsert，但是 the documentation 明确指出 upsert 不能与它一起使用：

Do not use the positional operator $ with upsert operations because inserts will use the $ as a field name in the inserted document.

$[<identifier>] 也不行：

If the upsert operation did not include an exact equality match and no matching documents were found to update, the upsert operation would error.

有没有办法不用多次访问数据库就可以做到这一点？

我尝试过的事情：

// Updating the path 'items' would create a conflict at 'items'
collection.updateOne(
  {_id: 0, 'items._id': 3},
  {$set: {'items.$.price': 30}, $setOnInsert: {items: []}}
)

// $[<identifier>] with upsert doesn't work
// The path 'items' must exist in the document in order to apply array updates.
collection.updateOne(
  {_id: 2},
  {$set: {'items.$[item].price': 30}},
  {arrayFilters: [{'item._id': 3}], upsert: true}
)

// Updating the path 'items' would create a conflict at 'items'
collection.updateOne(
  {_id: 0},
  {$set: {'items.$[item].price': 30}, $setOnInsert: {items: []}},
  {arrayFilters: [{'item._id': 3}], upsert: true}
)

Answer 1

作为D. SM said, you can use bulkWrite一次做多个操作：

const shopId = 0
collection.bulkWrite([
  // Remove any existing item
  {
    updateOne: {
      filter: {_id: shopId},
      update: {$pull: {items: {_id: 3}}}
    }
  },
  // Add the item with the updated price to the shop
  {
    updateOne: {
      filter: {_id: shopId},
      update: {
        $push: {items: {_id: 3, price: 30}}
      },
      upsert: true
    }
  }
])

$ 带 upsert 的位置更新运算符

$ positional update operator with upsert

javascript

mongodb

node.js

mongodb-nodejs-driver